Metals have conductivity of the order of (ohm^-1 m^-1):-

1. 10¹²

2. 10⁸

3. 10²

4. 10^-6
 

The specific conductance of a 0.1 M KCl solution at 23 °C is 0.012  Ω^–1 cm^–1. The resistance of cells containing the solution at the same temperature was found to be 55 Ω. The cell constant will be:

Which of the following aqueous solutions has the highest electrical conductivity?

1. 0.1 M Acetic acid

2. 0.1 M Chloroacetic acid

3. 0.1 M Fluoroacetic acid

4. 0.1 M Difluoroacetic acid

Equivalent conductances of NaCl, HCl and C₂H₅COONa at infinite dilution are 126.45, 426.16 and 91 ${\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2$. The equivalent conductance of C₂H₅COOH is : 

1. 201.28 ${\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2$

2. 390.71 ${\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2$

3. 698.28 ${\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2$

4. 540.48 ${\mathrm{\Omega }}^{-1}{\mathrm{cm}}^2$

Pick out the incorrect statement

1. Equivalent conductance increases with dilution

2. Molar conductance increases with dilution

3. Specific conductance increases with dilution

4. Specific resistance increases with dilution

The molar conductivity of a solution of AgNO₃ (considering the given data for this solution) at 298 K is:
(a) Concentration: 0.5 mol/dm³
(b) Electrolytic conductivity: 5.76×10^–3 S cm^–1

Aqueous solution of which of the following compounds is the best conductor of electric

current?

1. Acetic acid, C₂H₄O₂

2. Hydrochloric acid, HCl

3. Ammonia, NH₃

4. Fructose, C₆H₁₂O₆

For the cell (at 298 K)

Ag(s) | AgCl(s) | Cl^–(aq) || AgNO₃(aq) | Ag(s)

Which of the following is correct –

(1) The cell emf will be zero when [Ag⁺]_a = [Ag⁺]_c ([Ag⁺] in anodic compartment = [Ag⁺] in cathodic compartment)

(2) The amount of AgCl(s) precipitate in anodic compartment will decrease with the working of the cell.

(3) The concentration of [Ag⁺] = constant, in anodic compartment during working of cell.

(4) E_cell = E°_{Ag+ | Ag} –E°_{Cl–|AgCl|Ag} $\text{−}\frac{0.059}{1}\log \frac{1}{{\left[{\mathrm{Cl}}^{-}\right]}_{\mathrm{a}}}$

Equivalent conductivity of ${\mathrm{Fe}}_2{\left({\mathrm{SO}}_4\right)}_3$is related to molar conductivity by the expression:

1. ${\wedge }_{eq}$ = ${\wedge }_m$

2. ${\wedge }_{eq}$ = ${\wedge }_m/3$

3. ${\wedge }_{eq}$ = $3{\wedge }_m$

4. ${\wedge }_{eq}$ = ${\wedge }_m/6$

Specific conductance has the unit:

1. $oh{m}^{-1}<mspace\; width="1em"></mspace>c{m}^{-1}$                           

2. ohm.cm

3. $ohm<mspace\; width="1em"></mspace>c{m}^{-1}$                             

4. $oh{m}^{-1}.cm$