What is major product of following reaction ?

1.		2.
3.		4.

Which of the following statement is correct

(1)
(2)
(3)
(4)

(CH₃)₃CCI + (CH₃)₃C${\mathrm{O}}^{-}$ K⁺ → Product

1. S_N Product will be more

2. E₂ Product will be more

3. Both will be the same

4. None of the above

The product of following reacting is

(1)
(2)
(3)
(4)

Bromination of (E)-2-butenedioic acid gives

(1) (2R, 3S)-2, 3-dibromosuccinic acid

(2) (2R, 3R)-2, 3-dibroniosuccinic acid

(3) a mixture of (2R, 3R) and (2S, 3S)-2, 3-dibromosuccinic acid

(4) (2S, 3S)-2, 3-dibromosuccinic acid

Consider the following reaction:-

Which response contains all the correct statement about this process?
(1)Dehydration
(2)E₂ mechanism
(3)Carbon skeleton migration
(4)Most stable alkene will form
(5)Single-step reaction

(a)1,3        (b)1,2,3         (c)1,2,5          (d)1,3,4

$\underset{\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{PO}}_4}{\to }} \mathrm{OH} +$

In E₂ elimination, some compounds follow Hofmann's rule which means:

1. the double bond goes to the most substituted carbon

2. the compound is resistant to elimination

3. no double bond is formed

4. the double bond goes mainly towards the least substituted carbon

Dehydrogenation of ethanol to give ethanal is:$\left(1\right) \mathrm{additional} \mathrm{reaction}$
$\left(2\right) \mathrm{\alpha }-\mathrm{\alpha } \mathrm{elimination} \mathrm{reaction}$
$\left(3\right) \mathrm{\alpha }-\mathrm{\beta } \mathrm{elimination} \mathrm{reaction}$
$\left(4\right) \mathrm{\alpha }-\mathrm{\gamma } \mathrm{elimination} \mathrm{reaction}$

In which reaction product formation takes place by Saytzeff rule?

1. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{Br}}{|}}{\mathrm{C}}\mathrm{H}-{\mathrm{CH}}_3\stackrel{{\mathrm{CH}}_3\mathrm{ONa}/∆}{\to }$

2. ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{\mathrm{OH}}{|}}{\mathrm{C}}}-{\mathrm{CH}}_3\stackrel{\mathrm{conc}. {\mathrm{H}}_2{\mathrm{SO}}_4/∆}{\to }$

3. ${\mathrm{CH}}_3-\underset{\underset{{\mathrm{CH}}_3}{|}}{\overset{\stackrel{\mathrm{Br}}{|}}{\mathrm{C}}}-{\mathrm{CH}}_3\stackrel{\mathrm{alc}. \mathrm{KOH}/∆}{\to }$

4. ${\mathrm{CF}}_3-{\mathrm{CHCl}}_2\stackrel{\mathrm{alc}. \mathrm{KOH}/∆}{\to }$

In the given reaction:

${\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}-{\mathrm{CH}}_2-\mathrm{Br}\stackrel{\mathrm{alc}.\mathrm{KOH}/∆}{\to }\left[\mathrm{X}\right]$

[X] will be:

(1) $C{H}_3-C{H}_2-C=C{H}_2$
$I$
$C{H}_3$

(2) $C{H}_3-CH=C-C{H}_3$
$l$
$C{H}_3$

(3) $C{H}_2=CH-CH-C{H}_3$
$l$
$C{H}_3$

(4) $C{H}_3-CH=CH-C{H}_2-C{H}_3$