The octahedral complex will not show geometrical isomerism is :
(A and B are monodentate ligands)
1. [MA4B2]
2. [MA5B]
3. [MA2B4]
4. [MA3B3]
The total number of possible isomers for the complex compound[CuII(NH3)4][PtIICl4] are
1. 5
2. 6
3. 3
4. 4
The ionization isomer of [Cr(H2O)4Cl(NO2)]Cl is:
| 1. | [Cr(H2O)4(O2N)]Cl2 | 2. | [Cr(H2O)4Cl2](NO2) |
| 3. | [Cr(H2O)4Cl(ONO)]Cl | 4. | [Cr(H2O)4Cl2(NO2)].H2O |
Which of the following compounds exhibit geometrical isomerism?
1. [Pt(NH3)2Cl2]
2. [Zn(NH3)2Cl2]
3. [Pt(NH3)3Cl
4. All of these
The number of geometrical isomers possible for a square planar complex are
(1) 2
(2) 3
(3) 4
(4) 5
[Cr(en)2Br2]+ can show
(1) Optical isomerism
(2) Geometrical isomerism
(3) Both (1) and (2)
(4) Neither (1) nor (2)
How many hydrate isomers are possible for the molecular formula CoCl3,6H2O?
1. One
2. Two
3. Three
4. Four
Which of the following complex will show geometrical as well as optical isomerism ?
1. [Pt(NH3)2Cl2]
2. [Pt(NH3)Cl3]
3. [Pt(en)2Cl2]
4. [Pt(en)3]4+
Correct increasing order for the wavelengths of absorption in the visible region for the complexes of \(\text{Co}^{3+}\) is:
| 1. | \(\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}<\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}<\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}\) |
| 2. | \(\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}<\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}<\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\) |
| 3. | \(\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}<\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}<\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}\) |
| 4. | \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}<\left[\mathrm{Co}(\mathrm{en})_3\right]^{3+}<\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}\) |
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