If 10 gm of V2O5 is dissolved in acid and is reduced to V2+ by zinc metal, how many mole of I2 could be reduced by the resulting solution if it is further oxidised to VO2+ ions ? [Assume no change in state of Zn2+ions] (V = 51, O =16, I = 127) :

(1) 0.11 mole of I2

(2) 0.22 mole of I2

(3) 0.055 mole of I2

(4) 0.44 mole of I2

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Oxidation numbers of P in PO43-, of S in SO42- and that of Cr in Cr2O72- are respectively,

(a) +5, +6 and +6                      (b) +3, +6 and +5

(c) +5, +3 and +6                      (d) -3, +6 and +6

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The number of mole of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is:

(a) 35

(b) 45

(c) 25

(d) 1

 

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For the redox reaction MnO4+C2O42+H+Mn2++CO2+H2O the correct coefficients of the reactants for the balanced reaction are [IIT 1988, 92; BHU 1995; CPMT 1997; RPMT 1999; DCE 2000; MP PET 2003]

 

MnO4  

C2O42  

H+

(1)  

 2

5

16

(2)

16

5

2

(3)

5

16

2

(4)

2

16

5

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The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is: [CBSE PMT 2005]

(1) One fifth

(2) five

(3) One

(4) Two

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The compound YBa2Cu3O7 which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state [IIT 1994]

(1) 3/7

(2) 7/3

(3) 3

(4) 7

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In a balanced equation H2SO4+xHIH2S+yI2+zH2O, the values of x, y, z are [EAMCET 2003]

(1) x = 3, y = 5, z = 2

(2) x = 4, y = 8, z = 5

(3) x = 8, y = 4, z = 4

(4) x = 5, y = 3, z = 4

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