The relation amongst the three elements of Earth's magnetic field, namely horizontal component H, vertical component V and dip angle δ is: (BE=total magnetic field):

1. V=BEtanδ, H=BE

2. V=BEsinδ, H=BEcosδ

3. V=BEcosδ, H=BEsin δ

4. V=BE, H=BEtanδ 

 82%
From NCERT
NEET - 2019
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A proton and an \(\alpha\text{-}\)particle are accelerated from rest to the same energy. The de-Broglie wavelength \(\lambda_p\) and \(\lambda_\alpha\) are in the ratio:
1. \(2:1\)
2. \(1:1\)
3. \(\sqrt{2}:1\)
4. \(4:1\)

Subtopic:  De-broglie Wavelength |
 68%
From NCERT
NEET - 2019
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A truck is stationary and has a bob suspended by a light string in a frame attached to the truck. The truck suddenly moves to the right with an acceleration of \(a.\) In the frame of the truck, the pendulum will tilt:

1.  to the left and the angle of inclination of the pendulum with the vertical is \(\text{sin}^{-1} \left( \dfrac{a}{g} \right )\)
2.  to the left and the angle of inclination of the pendulum with the vertical is \(\text{cos}^{-1} \left ( \dfrac{a}{g} \right )\)
3.  to the left and the angle of inclination of the pendulum with the vertical is \(\text{tan}^{-1} \left ( \dfrac{a}{g} \right )\)
4.  to the left and the angle of inclination of the pendulum with the vertical is \(\text{tan}^{-1} \left ( \dfrac{g}{a} \right )\)
Subtopic:  Application of Laws |
 80%
From NCERT
NEET - 2019
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The time period of a geostationary satellite is \(24~\text{hr}\) at a height \(6R_E\) \((R_E\) is the radius of the Earth) from the surface of the earth. The time period of another satellite whose height is \(2.5R_E\) from the surface will be:
1. \(6\sqrt{2}~\text{hr}\) 2. \(12\sqrt{2}~\text{hr}\)
3. \(\frac{24}{2.5}~\text{hr}\) 4. \(\frac{12}{2.5}~\text{hr}\)
Subtopic:  Kepler's Laws |
 68%
From NCERT
NEET - 2019
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Two metal spheres, one of radius \(R\) and the other of radius \(2R\) respectively have the same surface charge density \(\sigma.\) They are brought in contact and separated.  What will be the new surface charge densities on them?
1. \(\sigma_{1}=\dfrac{5}{6}\sigma ,~\sigma_{2}=\dfrac{5}{6}\sigma\)
2. \(\sigma_{1}=\dfrac{5}{2}\sigma ,~\sigma_{2}=\dfrac{5}{6}\sigma\)
3. \(\sigma_{1}=\dfrac{5}{2}\sigma ,~\sigma_{2}=\dfrac{5}{3}\sigma\)
4. \(\sigma_{1}=\dfrac{5}{3}\sigma ,~\sigma_{2}=\dfrac{5}{6}\sigma\)
Subtopic:  Electric Potential |
 57%
From NCERT
NEET - 2019
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Two identical capacitors \(C_{1}\) and \(C_{2}\) of equal capacitance are connected as shown in the circuit. Terminals \(a\) and \(b\) of the key \(k\) are connected to charge capacitor \(C_{1}\) using a battery of emf \(V\) volt. Now disconnecting \(a\) and \(b\) terminals, terminals \(b\) and \(c\) are connected. Due to this, what will be the percentage loss of energy?

1. \(75\%\) 2. \(0\%\)
3. \(50\%\) 4. \(25\%\)
Subtopic:  Energy stored in Capacitor |
 65%
From NCERT
NEET - 2019
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The main scale of a vernier calliper has \(n\) divisions/cm. \(n\) divisions of the vernier scale coincide with \((n-1)\) divisions of the main scale. The least count of the vernier calliper is:
1. \(\dfrac{1}{(n+1)(n-1)}\) cm
2. \(\dfrac{1}{n}\) cm
3. \(\dfrac{1}{n^{2}}\) cm
4. \(\dfrac{1}{(n)(n+1)}\) cm

Subtopic:  Measurement & Measuring Devices |
 53%
From NCERT
NEET - 2019
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A sphere encloses an electric dipole with charges \(\pm3\times10^{-6}~\text C.\) What is the total electric flux through the sphere?
1. \(-3\times10^{-6}~\text{N-m}^2/\text C\) 
2. zero
3. \(3\times10^{-6}~\text{N-m}^2/\text C\)
4. \(6\times10^{-6}~\text{N-m}^2/\text C\)

Subtopic:  Gauss's Law |
 90%
From NCERT
NEET - 2019
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The work function of the photosensitive material is \(4.0~\text{eV}\). The longest wavelength of light that can cause photoelectric emission from the substance is (approximately):
1. \(3100~\text{nm}\)
2. \(966~\text{nm}\)
3. \(31~\text{nm}\)
4. \(310~\text{nm}\)

Subtopic:  Photoelectric Effect: Experiment |
 75%
From NCERT
NEET - 2019
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A body of mass \(m\) is kept on a rough horizontal surface (coefficient of friction = \(\mu).\) A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by \(\vec {F}\) where:
1. \(|{\vec {F}}| = mg+\mu mg\)
2. \(|\vec {F}| =\mu mg\)
3. \(|\vec {F}| \le mg\sqrt{1+\mu^2}\)
4. \(|\vec{F}| = mg\)

Subtopic:  Friction |
 75%
From NCERT
NEET - 2019
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