Q. No.Heat-killed S form Streptococcus extract treated with proteases is mixed with live R form Streptococcus cells and injected into living mice. What is most likely to happen?
1.
The mice would live.
2.
The mice would die.
3.
The mice's blood would have dead R cells.
4.
A new strain of Streptococcus will be present in mice.
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The addition of deoxyribonucleotides by DNA polymerase during DNA synthesis is an endergonic process. The source of energy used is:
| 1. | ATP |
| 2. | Energy from photons of light |
| 3. | Entropy created from protein digestion |
| 4. | The nucleotides themselves |
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It is believed that all organisms have arisen from a single distant ancestor. The strongest evidence for this would be:
| 1. | DNA stores genetic information in all organisms. |
| 2. | The genetic code is universally a triplet code. |
| 3. | The amino acids specified by particular triplets are almost always identical between any two organisms. |
| 4. | The genetic code is degenerate but unambiguous. |
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RNA polymerase is able to identify the template strand from the coding strand because of:
| 1. | promoter | 2. | initiator |
| 3. | transcription factor | 4. | start codon |
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hnRNA from the nucleus of a eukaryotic cell is hybridized with mature mRNA produced from it. Some regions loop out and represent:
1. excised introns
2. exons in the pre-mRNA
3. the poly-A tail in the pre-mRNA
4. introns to be excised later
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Wobble" pairing, a property of tRNA, put forth by Francis Crick is largely responsible for:
| 1. | the redundancy of the genetic code. |
| 2. | the conservation of the genetic message. |
| 3. | the large variety of amino acids encoded by the genetic code. |
| 4. | the excess of different kinds of tRNA that are required for all the amino acids. |
The amino acid sequence for a eukaryotic gene is placed in a plasmid just downstream of a promoter. Which of the following can be the most likely result?
| 1. | The cell would die because of the antigenicity of the eukaryotic proteins. |
| 2. | The prokaryotic cell will demonstrate the eukaryotic processes such as splicing. |
| 3. | An mRNA would form, but would it would be much longer than that formed directly from the template in the original eukaryote. |
| 4. | If the ribosome could bind the mRNA, a polypeptide that is longer than the one from the original eukaryote would be created. |
Using reverse transcriptase or gene synthesis has an advantage over the shotgun approach in obtaining a copy of the gene required as:
| 1. | the gene produced can easily be ligated to the vector |
| 2. | the gene produced is not a split gene |
| 3. | the gene produced does not require a promoter to be expressed |
| 4. | the gene produced does not require an ori to replicate |
The promoter site and the terminator site for transcription are located at:
| 1. | 3' (downstream) end and 5' (upstream) end, respectively of the transcription unit |
| 2. | 5' (upstream) end and 3' (downstream) end, respectively of the transcription unit |
| 3. | the 5' (upstream) end |
| 4. | the 3' (downstream) end |
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With regard to mature mRNA in eukaryotes:
| 1. | exons and introns do not appear in the mature RNA. |
| 2. | exons appear but introns do not appear in the mature RNA. |
| 3. | introns appear but exons do not appear in the mature RNA. |
| 4. | both exons and introns appear in the mature RNA. |
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