NEET and AIPMT NEET Chemistry Differentiations & Conversions - Organic Chemistry MCQ Questions Solved


A compound A of formula C3H6Cl2 on reaction with alkali can give B of formula C3H6O or C of formula C3H4. B on oxidation gave a compound of the formula C3H6O. C with dilute H2SO4 containing Hg2+ ion gave D of formula C3H6O, which with bromine and NaOH gave the sodium salt of C2H4O2. Then A is :

(a) CH3CH2CHCl2

(b) CH3CCl2CH3

(c) CH2ClCH2CH2Cl

(d) CH3CHClCH2Cl

 

Concept Videos :-

#13 | Conversion: Acid Derivative to Triple Bond (n to n)

Concept Questions :-

conversion chart for n to n carbon

(a) 

 

 or CH3CCH H+,Hg2+H2O CH3COCH+NaOHBr2 CHBr3 +CH3COONa
Since, B and D are different thus. B is CH3CH2CHO and so A is CH3CH2CHCl2.

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Identify the product (A) in following reaction series, CH3CNNa/C2H5OH(X)HNO2(Y)O(Z)Tollens reagent(A) :

(a) CH3CHO

(b) CH3CONH2

(c) CH3COOH

(d) CH- CH2-NHOH

Concept Videos :-

#13 | Conversion: Acid Derivative to Triple Bond (n to n)

Concept Questions :-

conversion chart for n to n carbon

(c) CH3CNNa/C2H5OHCH3CH2NH2HNO2CH3CH2OHOCH3CHOTollens reagentCH3COOH

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Vapour density of an organic compound is 23.0. It contains 52.17% of carbon and 13% of hydrogen. The compound gives iodoform test. The compound is:

(a) ethanol                               

(b) dimethyl ether

(c) acetone                             

(d) methanal

Concept Videos :-

#2 | Differentiation: Iodoform Reaction

Concept Questions :-

Iodoform Reaction

(a) Molar mass of compound  is 46 which is of ethanol. It also gives iodoform test.                               

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Compound (A), C8H9Br , gives a white precipitate when warmed with alcholic AgNO3. Oxidation of (A) gives an acid (B), C8H6O4. (B) easily forms anhydride on heating. Identify the compound (A).

(a)

 

(b)

 

(c)

 

(d)

 

Concept Videos :-

#19 | Conversion: Solved Problems on Aromatics: 1
#20 | Conversion: Solved Problems on Aromatics: 2
#21 | Conversion: Solved Problems on Aromatics: 3

Concept Questions :-

Aromatic Conversion

(b) 

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Which of the following will give yellow precipitate with I2/NaOH?

1. CH3-CO-O-CO-CH3

4.Both (2) and (3)

Concept Videos :-

#2 | Differentiation: Iodoform Reaction

Concept Questions :-

Iodoform Reaction

(4) 

Acetic anhydride under basic condition (hydroxide ion) gets hydrolysed to two molecules of acetic acid. This acid then converts into carboxylate ion, hence iodoform reaction is not possible.

 

 - I effect stabilises carbon ion, so option B can also give iodoform test.

Video Solution:

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A nitrogeneous substance X is treated with red P/I2,AgNO2, HNO2 and the product so formed is further treated with NaOH solution, which produces blue colouration. X can be

1. CH3CH2NH2       R   R'  R"  C  OH  Red P+I2     I      AgNO2     NO2

2 CH3CH2NO2

3. CH3CH2ONO

4 (CH3)2CHNO2

Concept Videos :-

#3 | Differentiation: 1st, 2nd & 3rd Degree Alcohol

Concept Questions :-

1st, 2nd & 3rd Degree Alcohol

(4) In Victor Meyer Test, secondary nitro compounds give blue colour.

R-CH2OH  Red P+I2 R-CH2-I  AgNO2  R-CH2-NO2
                                              

 

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The compound which reacts fastest with Lucas reagent at room temperature is:
1. Butan-1-ol
2. Butan-2-ol
3. 2-methylpropan-1-ol
4. 2-methylpropan-2-ol

Concept Videos :-

#3 | Differentiation: 1st, 2nd & 3rd Degree Alcohol

Concept Questions :-

1st, 2nd & 3rd Degree Alcohol

(4) The order of reactivity of alcohol towards Lucas reagent is: 3°> 2°> 1°

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Methanol and ethanol can be distinguished by the following:
1. By reaction with metallic sodium
2. By reaction with caustic soda
3. By heating with iodine and washing soda
4. By heating with zinc and inorganic mineral acid

Concept Videos :-

#6 | Differentiation: Alcohols & Phenols

Concept Questions :-

Alcohols & Phenols

(3) Ethanol can give iodoform reaction while methanol can't give.

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Identify (X) in the sequence :

C3H8O  (X) H2SO4K2Cr2O7 C3H6O WarmI2 +NaOH CHI3

(1) CH3-CH2-CH2OH

(2) 

(3) CH3-O-CH2-CH3

(4) CH3-CH2-CHO

Concept Videos :-

#2 | Differentiation: Iodoform Reaction

Concept Questions :-

Iodoform Reaction


(2)

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In order to accomplish the following conversion, what reagent and conditions would be required?

1. Cold sodium hydroxide

2. Hot conc. sodium hydroxide

3. Potassium tertiary butoxide and heat

4. Hot water

Concept Videos :-

#13 | Conversion: Acid Derivative to Triple Bond (n to n)

Concept Questions :-

conversion chart for n to n carbon

(3)

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