Reactivity order of halides for dehydrohalogenation is
(a) R-F>R-Cl>R-Br>R-I(b) R-I>R-Br>R-Cl>R-F(c) R-I>R-Cl>R-Br>R-F(d) R-F>R-I>R-Br>R-Cl
(b) F,Cl,Br and I are the elements of VII A group. In a group atomic radii increases from top to bottom and the bond dissociation energy decreases as
So, during dehydrohalogenation R-I bond breaks more easily than R-I bond. Hence, order of reactivity will be
The increasing order of hydrolysis of the following compounds:
(a) Higher is the stability of intermediate (carbocation), more is the reactivity of compound.
(ii) forms allyl carbocation, (iii) forms secondary carbocation and (i) forms phenyl carbocation.
What is major product of following reaction ?
(3) Dehydrohalogenation is an example of anti elimination.
Consider the given reaction below:
Which of these is true regarding the reaction shown above?
(1) the configuration of the chiral carbon remains same.
(2) the configuration of the chiral carbon gets inverted
(3) the compound formed as a product must be a dextro isomer
(4) the reactant is optically inactive but the product is obtained as a levo isomer.
(1) the configuration of the chiral carbon remains same because the priority of CN- and -COOH is same.
Product 2 is
(1) the ease of dehydrohalogenation of alkyl halide is:
Which of the following is formed by the thermal decomposition of the hydroxide of:
It is an example of Hoffman elimination
Read the following road map carefully
(1) Both the ethers obtained by the two routes have opposite but equal optical rotation.
(2) One of the ether is obtained as a racemic mixture.
(3) Step II & III both are SN2 reaction and both have inversion.
(4) Step II has inversion but step III has retention.