NEETprep Bank NEET Chemistry Amines Questions Solved


An organic compound A on reduction gives compound B which on reaction with chloroform and potassium hydroxide forms C. The compound C on catalytic reduction gives N-methylaniline. The compound A is                                                                                            

(a) nitrobenzene

(b) nitromethane

(c) methylamine

(d) aniline

(a)

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Acetamide and ethyl amine can be distinguished by reacting with             

(a) aq. HCl and heat

(b) aq. NaOH and heat

(c) acidified KMnO4

(d) bromine water

(b) When acetamide is heated with aq. NaOH it forms NH3 gas but ethylamine cannot form NH3.

 CH3CONH2 + H2ONaOHCH3COONa + NH3

CH3CH2NH2 + H2NaOHNo reaction

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Which of the following compound gives dye test

(1) Aniline                (2) Methylamine                  (3) Diphenylamine                  (4)Ethylamine

 

(1) Basically, all Azo dyes are derivatives of aniline.

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CH3CH2ClNaCNXNi/H2YAcetic anhydrideZ

In the above reaction sequence, Z is                                  

(a) CH3CH2CH2NHCOCH3

(b) CH3CH2CH2NH2

(c) CH3CH2CH2CONHCH3

(d) CH3CH2CH2CONHCOCH3

(a) CH3CH2Cl NaCNCH3-CH2-CNNi/H2CH3-CH2CH2NH2Acetic anhydrideCH3-CH2-CH2-NHCOCH3

                                     X                             Y                                            Z

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In the reaction, 

CH3CN +2H SnCl2HClXBoiling H2O  Y ,

the term Y is

(a) acetone

(b) ethanamine

(c) acetaldehyde

(d) dimethyl amine

(c) CH3CN  +2H SnCl2HClCH3-CH=NHBoilH2OCH3-CH=O

                                            X                               Y

                                        Imide                        Acetaldehyde

So, Y is acetaldehyde.

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Predict the product,                               

 

(a) Both aliphatic and aromatic secondary amines react with NaNO2 + HCl(HNO2) to form N-nitrosoamines which are insoluble in dilute mineral acids and separate out as neutral yellow oily compounds.

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Aniline in a set of reactions yielded a product                                                   

The structure of the product D would be

(a) C6H5CH2NH2

(b)C6H5NHCH2CH3

(c)C6H5NHOH

(d)C6H5CH2OH

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Intermediates formed during the reaction of RCONH2 with Br2 and KOH are                                

(a) RCONHBr and RNCO

(b) RNHCOBr and RNCO

(c) RNHBr and RCONHBr

(d) RCONBr2

(a)  The reaction, RCONH2 + Br2 + KOH RNH2

 is known as Hofmann bromamide reaction. The mechanism of this is given as:

 

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In a reaction of aniline a colored product C was obtained.

(d)

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Which one of the following on reduction with LiAlH4 yields a secondary amine?                   [2007]

(a) Methyl isocyanide

(b) Acetamide

(c) Methyl cyanide

(d) Nitroethane

(a) CH3-NC + 4[H] LiAlH4CH3NHCH3

                                         Dimethylamine

On catalytic reduction or with lithium aluminium hydride (LiAlH4) or with nascent hydrogen, alkyl isocyanide yield 2° amine whereas cyanide gives 1° amine on reduction.

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