The Williamson's synthesis reaction among the following is -

1.
2.
3.	\(C_2H_5I + C_2H_5ONa \rightarrow C_2H_5-O-C_2H_5 + NaI\)
4.

The major product of Williamson’s ether synthesis reaction would be:


1. Benzene
2. Methoxy benzene
3. Ethoxy benzene
4. Ethane

Match the following:

	List I		List II
i.	O2N-C6H5-OCH3 (p)	a.	4-Ethoxy-1,1-dimethylcyclohexane
ii.	C2H5OCH2-CH(CH3)2	b.	1-Chloro-2-methoxyethane
iii.	CH3OCH2CH2Cl	c.	1-Ethoxy-2-methylpropane
iv.		d.	1-Methoxy-4-nitrobenzene

Match the starting material in Column I with the products formed (Column II) in the reaction with HI.

	Column I		Column II
A.	${\mathrm{CH}}_3-\mathrm{O}-{\mathrm{CH}}_3$	1.
B.		2.
C.		3.
D.		4.	${\mathrm{CH}}_3-\mathrm{OH}+{\mathrm{CH}}_3\mathrm{I}$
		5.

Match the items of Column I with items of Column II.

Codes

Product C in the following sequence of reactions is:
\(C_2H_5Br \xrightarrow{NaOH\text{(aq)}}\ A \xrightarrow{Na}\ B\ \xrightarrow{CH_3I}\ C\)

Ether is more volatile than alcohol despite having the same molecular formula. This is due to -

1. Dipolar character of ethers

2. Alcohols having resonance structures

3. Intermolecular hydrogen bonding in ethers

4. Intermolecular hydrogen bonding in alcohols

In the following Williamson’s synthesis reaction,

CH₃CH₂ONa + CH₃-Br → ?

The product will be:

Select the correct option based on statements below:

Ethyl chloride is converted into diethyl ether by -