The boiling point of ethanol is higher than that of dimethyl ether due to the presence of

1.	H-bonding in ethanol	2.	H-bonding in dimethyl ether
3.	-CH3 group in ethanol	4.	-CH3 group in dimethyl ether

The correct order of the acidic strength for the above compounds is -

(I)	(II)	(III)

1. I > II > III                           

2. III > I > II

3. II > III > I                           

4. I > III > II

The most acidic compound among the following is:

1.	ClCH2-CH2OH	2.
3.		4.

The formula for allyl alcohol is- 

1. CH₃-CH=CHOH                                  

2. CH₂=CHCH₂OH

3. HOCH₂CH₂CH₃                                     

4. None of the above.

The product A in the below mentioned reaction is:
 \(\xrightarrow[]{H_{2}O/H^{+}} \ \underset{(major)}{A} \ + \ \underset{(minor)}{B}\)        

1.		2.
3.		4.

Propan-1-ol may be prepared by reaction of propene with -              

1. CH₃COOH                                         

2. H₃BO₃

3. B₂H₆/NaOH-H₂O₂                               

4. H₂SO₄/H₂O     

The Williamson's synthesis reaction among the following is -

1.
2.
3.	\(C_2H_5I + C_2H_5ONa \rightarrow C_2H_5-O-C_2H_5 + NaI\)
4.

The ionisation constant of phenol is higher than that of ethanol because -                   

1. Phenoxide ion is bulkier than ethoxide

2. Phenoxide ion is a stronger base than ethoxide

3. Phenoxide ion is stabilised through delocalisation

4. Phenoxide ion is less stable than ethoxide

The best method to prepare cyclohexene from cyclohexanol is by using:

Given is a reaction for your reference:

\(CH_3CH_2CH_2OH \xrightarrow[160\ - \ 180 ^\circ C]{Conc.\ H_2SO_4}\ X\ \xrightarrow{Br_2}\ Y\)
\( Y\ \xrightarrow[2.\ NaNH_2]{1.\ Alc.\ KOH}\ Z\)

The final product Z is:

1.		2.
3.		4.	\(CH_3-C\equiv CH\)