Given is a reaction for your reference:

\(CH_3CH_2CH_2OH \xrightarrow[160\ - \ 180 ^\circ C]{Conc.\ H_2SO_4}\ X\ \xrightarrow{Br_2}\ Y\)
\( Y\ \xrightarrow[2.\ NaNH_2]{1.\ Alc.\ KOH}\ Z\)

The final product Z is:

1.  2.
3. 4.  \(CH_3-C\equiv CH\)

Subtopic:  Alcohols: Preparation & Properties |
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The best method to prepare cyclohexene from cyclohexanol is by using:

1. conc. HCl + ZnCl2 2. conc. H3PO4
3. HBr 4. conc. HCl
Subtopic:  Alcohols: Preparation & Properties | Mechanism of Dehydration, Methanol & Ethanol |
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The ionisation constant of phenol is higher than that of ethanol because -                   

1. Phenoxide ion is bulkier than ethoxide

2. Phenoxide ion is a stronger base than ethoxide

3. Phenoxide ion is stabilised through delocalisation

4. Phenoxide ion is less stable than ethoxide

Subtopic:  Alcohols: Preparation & Properties | Phenols: Preparation & Properties |
 81%
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The Williamson's synthesis reaction among the following is -

1.
2.
3.  \(C_2H_5I + C_2H_5ONa \rightarrow C_2H_5-O-C_2H_5 + NaI\)
4. 
Subtopic:  Ethers: Preparation & Properties, Uses |
 93%
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Propan-1-ol may be prepared by reaction of propene with -              

1. CH3COOH                                         

2. H3BO3

3. B2H6/NaOH-H2O2                               

4. H2SO4/H2O     

Subtopic:  Alcohols: Preparation & Properties |
 82%
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The product A in the below mentioned reaction is:
 \(\xrightarrow[]{H_{2}O/H^{+}} \ \underset{(major)}{A} \ + \ \underset{(minor)}{B}\)

1.    2.  
3.   4.  
 

Subtopic:  Alcohols: Preparation & Properties |
 74%
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The formula for allyl alcohol is- 

1. CH3-CH=CHOH                                  

2. CH2=CHCH2OH

3. HOCH2CH2CH3                                     

4. None of the above.

Subtopic:  Alcohols: Preparation & Properties |
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The most acidic compound among the following is:

1.   ClCH2-CH2OH 2.  
3.   4.   
Subtopic:  Phenols: Preparation & Properties |
 90%
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The correct order of the acidic strength for the above compounds is -

     (I)       (II)       (III)

1. I > II > III                           

2. III > I > II

3. II > III > I                           

4. I > III > II

Subtopic:  Phenols: Preparation & Properties |
 94%
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The boiling point of ethanol is higher than that of dimethyl ether due to the presence of

1. H-bonding in ethanol 2. H-bonding in dimethyl ether
3. -CH3 group in ethanol 4. -CH3 group in dimethyl ether

Subtopic:  Alcohols: Preparation & Properties |
 91%
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