An aromatic compound A (C₈H₁₀O) gives the following tests with the given reagents.

The structure of  'A' is:

1.		2.
3.		4.

Compound Y,  C₇H₈O is insoluble in water, dil HCI and aqueous NaHCO₃. It dissolves in dilute NaOH. When Y is treated with bromine water it is converted rapidly into a compound of formula C₇H₅OBr₃.  The structure of Y is:

1.		2.
3.		4.

Compounds I and II can be distinguished by using reagent:

1. NaNO₂/HCl

2. Br₂/H₂O

3. HCl/ZnCl₂ (anhydrous)

4. Cu₂Cl₂ + NH₄OH

The correct order of dehydration of compounds (i), (ii) and (iii) by conc. H₂SO₄ is:

(i)
(ii)
(iii)

1. (i) > (iii) > (ii)                                             

2. (i) > (ii) > (iii)

3. (ii) > (i) > (iii)                                             

4. (ii) > (iii) > (i)

Ether cannot be produced as a major product by the reaction of- 

1.	CH3CH2Cl + Ag2O(dry)  →
2.	(CH3)3CCl + CH3CH2O-Na+  →
3.
4.

The labeled -O¹⁸ will be:


1. H₂O

2. Methyl benzoate

3. Both 1 and 2

4. Benzoic acid

Product (A) in the below mentioned reaction is:
 

1.

2.

3.

4.

The compound that is most prone to oxidation is-

1.	CH3-CHOH-CH3	2.
3.	CH3-CH2-O-CH2-CH3	4.

Product (P) is:

1.		2.
3.		4.