Gadolinium belongs to 4f series. It’s atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?

1. Xe4 f8 6d2

2. Xe4 f9 5s1

3. Xe4 f7 5d16s2

4. Xe4 f6 5d26s2

Subtopic:  f-Block Elements- Properties & Uses |
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Assuming complete ionization, same moles of which of the following compounds will require the least amount of acidified KMnO4 for complex oxidation?

1. FeSO4

2. FeSO3

3. FeC2O4

4. FeNO22

Subtopic:  d-Block Elements- Properties & Uses |
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Because of lanthanoid contraction, which of the following pairs of elements have nearly same atomic radii? (Numbers in the parenthesis are atomic numbers).
1. Ti (22) and Zr (40)
2. Zr (40) and Nb (41)
3. Zr (40) and Hf (72)
4. Zr (40) and Ta (73)

Subtopic:  f-Block Elements- Properties & Uses | Lanthanoid /actinoids Contraction |
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Which of the following processes does not involve oxidation of iron?
1. Rusting of iron sheets
2. Decolourisation of blue CuSO4 solution by iron
3. Formation of Fe(CO)from Fe
4. Liberation of H2 from steam by iron at high temperature

Subtopic:  d-Block Elements- Properties & Uses |
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The pair of compounds that can exist together is:

1. FeCl3, SnCl2

2. HgCl, SnCl2

3. FeCl2, SnCl2

4. FeCl3, Kl

Subtopic:  d-Block Elements- Properties & Uses |
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In acidic medium, H2O2 changes Cr2O7–2 to CrO5 which has two (–O – O–) bonds. Oxidation state of Cr in CrO5 is :

1. +5

2. +3

3. +6

4. -10

Subtopic:  Chemistry of Mn and Cr Compounds |
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Reason of lanthanoid contraction is:

1. Negligible screening effect of 'f' orbitals

2. Increasing nuclear charge

3. Decreasing nuclear charge

4. Decreasing screening effect

Subtopic:  Lanthanoid /actinoids Contraction |
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Identify the correct order of solubility in aqueous medium :
1. ZnS > Na2S > CuS
2. Na2S > CuS > ZnS
3. Na2S > ZnS > Cus
4. Cus > ZnS > Na2S

 

Subtopic:  d-Block Elements- Properties & Uses |
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Diamagnetic lanthanoid ion among the following is -
(At nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)
 
1. Sm2+
2. Eu2+
3. Yb2+
4. Ce2+

 

Subtopic:  f-Block Elements- Properties & Uses |
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KMnO4 can be prepared from K2MnO4 as per the reaction: 
3MnO42-+2H2O2MnO4-+MnO2+4OH-
The reaction can go to completion by removing OH ions by adding:
1. KOH
2. CO2
3. SO2
4. HCl
Subtopic:  Chemistry of Mn and Cr Compounds |
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