| Statement I: | Heating NaCl with concentrated \(H_2SO_4\) and \(MnO_2\) results in oxidation of Mn. |
| Statement II: | Heating NaI with concentrated \(H_2SO_4\) and \(MnO_2\) results in reduction of Mn. |
| 1. | Statement I is incorrect but Statement II is correct. |
| 2. | Both Statement I and Statement II are correct. |
| 3. | Both Statement I and Statement II are incorrect. |
| 4. | Statement I is correct but Statement II is incorrect. |
| 1. | 1.5 moles | 2. | 7.5 moles |
| 3. | 2.5 moles | 4. | 5.0 moles |
The manganate and permanganate ions are tetrahedral, due to:
| 1. | The π-bonding involves the overlap of d-orbitals of oxygen with d-orbitals of manganese. |
| 2. | The π-bonding involves the overlap of p-orbitals of oxygen with d-orbitals of manganese. |
| 3. | Absence of π-bonding. |
| 4. | The π-bonding involves the overlap of p-orbitals of oxygen with p-orbitals of manganese. |
When neutral or faintly alkaline is treated with potassium iodide, iodide ion is converted into 'X'. 'X' is:
1.
2.
3.
4.
A gas that can readily decolorize an acidified KMnO4 solution is:
| 1. | SO2 | 2. | NO2 |
| 3. | P2O5 | 4. | CO2 |
SO2 is passed through an acidified K2Cr2O7 solution.
The correct statement among the following regarding the above experiment is:
1. The solution gets decolorized.
2. SO2 gets reduced.
3. Green coloured Cr2(SO4)3 gets formed.
4. The solution turns blue.
In acidic medium, H2O2 changes Cr2O7–2 to CrO5 which has two (–O – O–) bonds.
The oxidation state of Cr in CrO5 is:
1. +5
2. +3
3. +6
4. -10