Maximum oxidation state is shown by:

1. La 2. Gd
3. Eu 4. Am
Subtopic:  f-Block Elements- Properties & Uses |
Level 3: 35%-60%
AIPMT - 1998
Hints

An incorrect statement among the following is :

1. La(OH)3 is less basic than Lu(OH)3
2. In Lanthanide series, ionic radius of  Ln+3 ions decreases.
3. La is an element of a transition and not of Lanthanide series.
4. The atomic radius of Zr and Hf are the same because of Lanthanide contraction.
Subtopic:  f-Block Elements- Properties & Uses |
 75%
Level 2: 60%+
AIPMT - 2001
Hints

The general electronic configuration of lanthanoids is:

1. (n – 2) f 1–14 (n – 1) s2 p6 d0–1 ns2

2. (n – 2) f 10–14 (n – 1) d0–1 ns2

3. (n – 2) f 0–14 (n – 1) d10 ns2

4. (n – 2) d0–1 (n – 1) f 1–14 ns2

Subtopic:  f-Block Elements- Properties & Uses |
 53%
Level 3: 35%-60%
AIPMT - 2002
Hints

advertisementadvertisement

The correct order of ionic radii of Y3+, La3+, Eu3+, and Lu3+ is:

(Atomic nos. Y = 39, La = 57, Eu = 63, Lu = 71)

1. Y3+ < La3+ < Eu3+ < Lu3+

2. Y3+ < Lu3+ < Eu3+ < La3+

3. Lu3+ < Eu3+ < La3+ < Y3+

4. La3+ < Eu3+ < Lu3+ < Y3+

Subtopic:  f-Block Elements- Properties & Uses |
 57%
Level 3: 35%-60%
AIPMT - 2003
Hints

The main reason for a larger number of oxidation states exhibited by the actinoids than the corresponding lanthanoids is:

1. Larger atomic size of actinoids than the lanthanoids
2. More energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
3. Lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
4. Greater reactive nature of the actinoids than the lanthanoids
Subtopic:  d-Block Elements- Properties & Uses | f-Block Elements- Properties & Uses |
 80%
Level 1: 80%+
AIPMT - 2005
Hints