The cell constant of a conductivity cell- 1. Changes with the change of electrolyte. 2. Changes with the change of concentration of electrolyte. 3. Changes with the temperature of the electrolyte. 4. Remains constant for a cell.

Subtopic:  Conductance & Conductivity |
80%
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The correct statement about charging of the lead storage battery is:

 1 PbSO4 anode is reduced to Pb. 2 PbSO4 cathode is reduced to Pb. 3 PbSO4 cathode is oxidised to Pb. ​​​​​​ 4 PbSO4 anode is oxidised to PbO2.

Subtopic:  Batteries & Salt Bridge |
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$$\Lambda _{m(NH_{4}OH)}^{o}$$ is equal to -
1. $$\Lambda _{m(NH_{4}OH)}^{o} \ + \ \Lambda _{m(NH_{4}Cl)}^{o} \ - \ \Lambda _{m(HCl)}^{o}$$
2. $$\Lambda _{m(NH_{4}Cl)}^{o} \ + \ \Lambda _{m(NaOH)}^{o} \ - \ \Lambda _{m(NaCl)}^{o}$$
3. $$\Lambda _{m(NH_{4}Cl)}^{o} \ + \ \Lambda _{m(NaCl)}^{o} \ - \ \Lambda _{m(NaOH)}^{o}$$
4. $$\ \Lambda _{m(NaOH)}^{o} \ + \ \Lambda _{m(NaCl)}^{o}\ - \ \Lambda _{m(NH_{4}Cl)}^{o}$$

Subtopic:   Kohlrausch Law & Cell Constant |
88%
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The half-cell reaction at the anode during the electrolysis of aqueous sodium chloride solution  is represented by :

1. Na+(aq) + e- ⟶ Na(s) ; $$E_{cell}^{o} \ = \ -2.71 \ V$$

2. 2H2O(l) ⟶ O2(g) + 4H+(aq) + 4e; $$E_{cell}^{o}$$ = 1.23 V

3. H+(aq) + e-$$\frac{1}{2}$$H2(g) ; $$E_{cell}^{o}$$ = 0.00 V

4. Cl-(aq) ⟶ $$\frac{1}{2}$$Cl2(g) + e- ; $$E_{cell}^{o}$$

Subtopic:  Electrolytic & Electrochemical Cell |
68%
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The positive value of the standard electrode potential of Cu2+ / Cu indicates that-

 (a) This redox couple is a stronger reducing agent than the H+ /H2 couple (b) This redox couple is a stronger oxidising agent than H+ /H2 (c) Cu can displace H2 from acid. (d) Cu cannot displace H2 from acid.

1. (a, b)
2. (b, c)
3. (c, d)
4. (b, d)

Subtopic:  Electrochemical Series | Electrolytic & Electrochemical Cell |
72%
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${\mathrm{E}}_{\mathrm{Cell}}^{°}$ of some half cell reactions are given below.

I.

II.

III.

The correct choice among the given is -

 a. In dilute sulphuric acid solution, hydrogen will be reduced at cathode b. In concentrated sulphuric acid solution, water will be oxidised at anode c. In dilute sulphuric acid solution, water will be oxidised at anode d. In dilute sulphuric acid solution, SO42- ion will be oxidised to tetrathionate ion at anode

Choose the correct option
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

Subtopic:  Electrolytic & Electrochemical Cell |
60%
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${\mathrm{E}}_{\mathrm{cell}}^{\mathrm{o}}$= 1.1 V for Daniel cell. Which of the following expressions are correct descriptions of the state of equilibrium in this cell?

(a) 1.1 = KC

(b) $\frac{2.303\mathrm{RT}}{2\mathrm{F}}{\mathrm{logK}}_{\mathrm{C}}=1.1$

(c) ${\mathrm{logK}}_{\mathrm{C}}=\frac{2.2}{0.059}$

(d) log KC = 1.1

The correct choice among the given is -

1. (a, b)

2. (b, c)

3. (c, d)

4. (a, d)

Subtopic:  Nernst Equation |
85%
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The conductivity of an electrolytic solution depends on

a. Nature of the electrolyte

b. Concentration of the electrolyte

c. Power of AC source

d. Distance between the electrodes
The correct statements from the four statements given above are:
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, d)

Subtopic:  Conductance & Conductivity |
79%
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${\mathrm{\Lambda }}_{\mathrm{m}}^{°}{\mathrm{H}}_{2}\mathrm{O}$ can be represented by-

a.  ${{\Lambda }^{°}}_{m\left(\mathrm{HCl}\right)}+{{\Lambda }^{°}}_{m\left(\mathrm{NaOH}\right)}°-{\Lambda }_{m\left(\mathrm{NaCl}\right)}°$

b.  ${{\Lambda }^{°}}_{m\left({\mathrm{HNO}}_{3}\right)}+{{\Lambda }^{°}}_{m\left({\mathrm{NaNO}}_{3}\right)}-{\Lambda }_{m\left(\mathrm{NaOH}\right)}^{°}$

c.  ${{\Lambda }^{°}}_{m\left({\mathrm{HNO}}_{3}\right)}+{{\Lambda }^{°}}_{m\left(\mathrm{NaOH}\right)}-{\Lambda }_{m\left({\mathrm{NaNO}}_{3}\right)}^{°}$

d.  ${{\Lambda }^{°}}_{m\left({\mathrm{NH}}_{4}\mathrm{OH}\right)}+{{\Lambda }^{°}}_{\mathrm{m}\left(\mathrm{HCl}\right)}-{{\Lambda }^{°}}_{\mathrm{m}\left({\mathrm{NH}}_{4}\mathrm{Cl}\right)}$

1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

Subtopic:   Kohlrausch Law & Cell Constant |
73%
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What will happen during the electrolysis of an aqueous solution of CuSO4 by using platinum electrodes?

 (a) Copper will deposit at cathode (b) Copper will deposit at the anode (c) Oxygen will be released at the anode (d) Copper will dissolve at the anode

The correct choice among the given is -
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)

Subtopic:  Faraday’s Law of Electrolysis |
79%
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