The emf of the cell in which the following reaction takes place is-

Ni(s)+2Ag+(0.002 M) →Ni2+(0.160 M) + 2Ag(s)
( Given that \(E_{cell}^{o}\)= 1.05 V)

1. Ecell= 9.14 V
2. Ecell= 0.0914 V
3. Ecell= 0.00914 V
4. Ecell= 0.914 V

Subtopic:  Nernst Equation |
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