# Assertion(A): The conductivity of a solution decreases with dilution. Reason(R): Conductivity of a solution depends on the number of ions and the number of ions decreases when the solution is diluted. 1. Both assertion and reason are true, and the reason is the correct explanation of the assertion. 2. Both assertion and reason are true, but the reason is not the correct explanation of the assertion. 3. Assertion is true but reason is false. 4. Assertion is false but reason is true.

Subtopic:  Conductance & Conductivity |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1.

The dissociation constant of methanoic acid is-

Given λ°(H+)= 349.6 S cm2 mol−1 and λ°(HCOO) = 54.6 S cm2 mol

1. $$1.27×10^{-4}mol ~L^{−1}$$
2. $$5.17×10^{-5}mol ~L^{−1}$$
3. $$3.67×10^{-4}mol ~L^{−1}$$
4. $$4.87×10^{-5}mol ~L^{−1}$$

Subtopic:   Kohlrausch Law & Cell Constant |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The number of electrons flow through the wire when a current of 0.5 ampere flows through a metallic wire for 2 hours, is-

1. $$6.25×10^{22}$$
2. $$2.25×10^{22}$$
3 $$8.25×10^{22}$$
4. $$4.25×10^{22}$$

Subtopic:  Faraday’s Law of Electrolysis |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The metals among the following that can be  extracted electrolytically is -
1. K
2. Na
3. Al
4. All of the above

Subtopic:  Electrochemical Series |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

Consider the reaction: $$Cr_{2}O_{7}^{2-}$$ + 14H++ 6e→2Cr3+ + 7H2O
The quantity of electricity in coulombs needed to reduce 1 mol of $$Cr_{2}O_{7}^{2-}$$ is-

1. 5F
2. 3F
3. 6F
4. 2F
Subtopic:  Faraday’s Law of Electrolysis |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The compound among the following that can be used as fuels is-

1. Methane
2. Methanol
3. Sulphuric acid
4. Both 1 and 2
Subtopic:  Batteries & Salt Bridge |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

Rusting of iron is envisaged as setting up of an electrochemical cell because:

1. Oxidation of iron takes place during rusting.
2. Reduction of iron takes place.
3. Iron shows disproportionation reaction.
4. Oxygen is getting oxidised.

Subtopic:  Batteries & Salt Bridge |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The cell in which the following reactions occurs:

2Fe3+(aq)+2I-(aq)→2Fe2+(aq)+I2(s) has $$E_{cell}^{o}$$= 0.236 V at 298 K.

The standard Gibbs energy of the cell reaction is −45.54 kJ mol−1 . The value of equilibrium constant  of the cell reaction is

1. 10.27 × 109
2. 9.57 × 107
3. 12.17 × 108
4. 7.17 × 106

Subtopic:  Relation between Emf, G, Kc & pH |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The cell in which the following reactions occurs:

2Fe3+(aq)+2I-(aq)→2Fe2+(aq)+I2(s) has $$E_{cell}^{o}$$= 0.236 V at 298 K.

The standard Gibbs energy of the cell reaction is -

1.   41.14 kJ mol−1
2.   45.54 kJ mol−1
3. −49.94 kJ mol−1
4. −45.54 kJ mol−1

Subtopic:  Relation between Emf, G, Kc & pH |
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The emf of the cell in which the following reaction takes place is-

Ni(s)+2Ag+(0.002 M) →Ni2+(0.160 M) + 2Ag(s)
( Given that $$E_{cell}^{o}$$= 1.05 V)

1. Ecell= 9.14 V
2. Ecell= 0.0914 V
3. Ecell= 0.00914 V
4. Ecell= 0.914 V

Subtopic:  Nernst Equation |