An increase in equivalent conductance of a strong electrolyte with dilution is mainly due to:

 1 increase in ionic mobility of ions 2 100% ionization of electrolyte at normal dilution 3 increase in both, i.e, number of ions and ionic mobility of ions 4 increase in the number of ions

Subtopic:  Conductance & Conductivity |
AIPMT - 2010
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The correct expression that  represents the equivalent conductance at infinite dilution of $A{l}_{2}{\left(S{O}_{4}\right)}_{3}$ is:

(Given that ${\wedge }_{A{l}^{3+}}^{°}$ $and$ ${\wedge }_{S{O}_{4}^{2-}}^{°}$ are the equivalent conductances at infinite dilution of the respective ions)

1. ${\wedge }_{A{l}^{3+}}^{°}$ $+$ ${\wedge }_{S{O}_{4}^{2-}}^{°}$

2. $\left({\wedge }_{A{l}^{3+}}^{°}\right)$ $+$ ${\wedge }_{S{O}_{4}^{2-}}^{°}×6$

3. $\frac{1}{3}{\wedge }_{A{l}^{3+}}^{°}$ $+\frac{1}{2}$ ${\wedge }_{S{O}_{4}^{2-}}^{°}$

4. $2{\wedge }_{A{l}^{3+}}^{°}$ $+3$ ${\wedge }_{S{O}_{4}^{2-}}^{°}$

Subtopic:  Conductance & Conductivity |
60%
AIPMT - 2010
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
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