Consider the half-cell reduction reaction:
\(\text{Mn}^{2+}+2e^-\rightarrow \text{Mn},\ E^{0}= -1.18~ \text V \) 
\(\text{Mn}^{2+}\rightarrow \text{Mn}^{3+}+e^-,\ E^{0}= -1.5~ \text V \)

The \(E^{0}\) for the reaction \(\mathrm{3\ Mn^{2+}\rightarrow Mn^{0}+2Mn^{3+} }\) and possibility of the forward reaction are respectively:
 
1. –4.18 V and Yes 2. +0.33 V and Yes
3. +2.69 V and No 4. –2.69 V and No

Subtopic:  Electrode & Electrode Potential |
 53%
From NCERT
NEET - 2013
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How many grams of cobalt metal will be deposited when a solution of cobalt (II) chloride is electrolyzed with a current of 10 amperes for 109 minutes?
(1 Faraday = 96,500 C; Atomic mass of Co = 59 u)
 
1. 4.0 2. 20.0
3. 40.0 4. 0.66
Subtopic:  Faraday’s Law of Electrolysis |
 71%
From NCERT
NEET - 2013
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Consider the following relations for emf of an electrochemical cell:

(a) emf of cell = (Oxidation potential of anode) – (Reduction potential of cathode)
(b) emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(c) emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(d) emf of cell = (Oxidation potential of anode) – (Oxidation potential of cathode)

The correct relation among the given options is: 

1. (a) and (b) 2. (c) and (d)
3. (b) and (d) 4. (c) and (a)
Subtopic:  Electrode & Electrode Potential |
 68%
From NCERT
AIPMT - 2010
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The correct expression that  represents the equivalent conductance at infinite dilution of Al2(SO4)3 is:

(Given that Al3+° and SO42-° are the equivalent conductances at infinite dilution of the respective ions)

1. Al3+° + SO42-°

2. Al3+° + SO42-°×6

3. 13Al3+° +12 SO42-°

4. 2Al3+° +3 SO42-°

Subtopic:  Conductance & Conductivity |
 60%
AIPMT - 2010
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Molar conductivities (°m) at infinite dilution of
NaCl, HCl, and CH3COONa are 126.4, 425.9, and 91.0 S cm2 mol–1 respectively.
 (°m)  for CH3COOH  will be: 

1. \(180.5~S~cm^2~mol^{-1}\) 2. \(290.8~S~cm^2~mol^{-1}\)
3. \(390.5~S~cm^2~mol^{-1}\) 4. \(425.5~S~cm^2~mol^{-1}\)
Subtopic:   Kohlrausch Law & Cell Constant |
 90%
From NCERT
AIPMT - 2012
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The Gibb's energy for the decomposition of \(\mathrm{A l_{2} O_{3}}\) at \(\mathrm{500~ ^\circ C}\) is as follows: 

2/3Al2O3 → 4/3Al + O2 ; ∆rG = + 960 k J mol–1

The potential difference needed for the electrolytic reduction of aluminium oxide (Al2O3) at \(\mathrm{500~ ^\circ C}\) is at least,

1. 3.0 V 

2. 2.5 V 

3. 5.0 V 

4. 4.5 V 

Subtopic:  Relation between Emf, G, Kc & pH |
 61%
From NCERT
AIPMT - 2012
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A hypothetical electrochemical cell is shown below.
A|A+(x M) || B+(y M)|B
The Emf measured is +0.20 V. The cell reaction is:

1. A+ + B → A + B+

2.  A+ + e- → A ; B+ + e- → B

3. The cell reaction cannot be predicted.

4. A + B+ → A+ + B

Subtopic:  Electrochemical Series | Nernst Equation |
 75%
From NCERT
AIPMT - 2006
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If EFe2+/Feo = -0.441 V and  EFe3+/Fe2+o = 0.771 V, the standard emf of the reaction: 

Fe + 2Fe3+→ 3Fe2+ will be:

1. 0.330 V 2. 1.653 V
3. 1.212 V 4. 0.111 V
Subtopic:  Electrode & Electrode Potential |
 71%
From NCERT
AIPMT - 2006
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In producing chlorine through electrolysis, 100 W power at 125 V is being consumed.
The liberation of chlorine per min is:
(ECE of chlorine is 0.367×10-6 kg/C)
1. 17.6 mg 2. 21.3 mg
3. 24.3 mg 4. 13.6 mg
Subtopic:  Faraday’s Law of Electrolysis |
 63%
From NCERT
AIPMT - 2006
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The efficiency of a fuel cell is given by:

1. HG

2. GS

3. GH

4. SG

Subtopic:  Batteries & Salt Bridge |
 65%
AIPMT - 2007
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