- 1(current)
Q. No.The number of electrons flow through the wire when a current of 0.5 ampere flows through a metallic wire for 2 hours, is-
1. \(6.25×10^{22}\)
2. \(2.25×10^{22}\)
3 \(8.25×10^{22}\)
4. \(4.25×10^{22}\)
Subtopic: Faraday’s Law of Electrolysis |
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Consider the reaction:
\(Cr_{2}O_{7}^{2-}\) + 14H++ 6e−→2Cr3+ + 7H2O
The quantity of electricity in coulombs needed to reduce 1 mol of \(Cr_{2}O_{7}^{2-}\) is-
1. 5F
2. 3F
3. 6F
4. 2F
\(Cr_{2}O_{7}^{2-}\) + 14H++ 6e−→2Cr3+ + 7H2O
The quantity of electricity in coulombs needed to reduce 1 mol of \(Cr_{2}O_{7}^{2-}\) is-
1. 5F
2. 3F
3. 6F
4. 2F
Subtopic: Faraday’s Law of Electrolysis |
75%
From NCERT
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
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- 1(current)
Q. No.
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