The standard cell potential of the following cell \(\mathrm{{Zn}\left|{Zn}^{2+}({aq}) \| {Fe}^{2+}({aq})\right| {Fe}~\text{ is }~0.32 {~V}}.\) Calculate the standard Gibbs energy change for the reaction:
\(\mathrm{{Zn}({s})+{Fe}^{2+}({aq}) \rightarrow {Zn}^{2+}({aq})+{Fe}({s})}\)

(Given : \(1 \mathrm{~F}=96487 \mathrm{C} mol^{-1}\))
1. \(-61.75 \mathrm{{~kJ} {~mol}}^{-1}\) 2. \(+5.006 \mathrm{{~kJ} {~mol}}^{-1}\)
3. \(-5.006 \mathrm{{~kJ} {~mol}}^{-1}\) 4. \(+61.75 \mathrm{{~kJ} {~mol}}^{-1}\)
Subtopic:  Relation between Emf, G, Kc & pH |
 84%
Level 1: 80%+
NEET - 2024
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
Assertion (A): In equation \(\Delta_{\mathrm{r}} \mathrm{G}=-\mathrm{nFE} _{\text {cell }}, \) value \(\mathrm{\Delta_rG }\) depends on n. 
Reason (R): \(\mathrm{E_{cell} }\) is an intensive property and \(\mathrm{\Delta_rG }\)  is an extensive property. 
 
1. (A) is False but (R) is True. 
2. Both (A) and (R) are True and (R) is the correct explanation of (A)
3. Both (A) and (R) are True and (R) is not the correct explanation of (A)
4. (A) is True but (R) is False.
Subtopic:  Relation between Emf, G, Kc & pH |
 59%
Level 3: 35%-60%
NEET - 2023
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Standard electrode potential for the cell with cell reaction
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)
is 1.1 V. Calculate the standard Gibbs energy change for the cell reaction. (Given F = 96487 C mol–1)
1. –200.27 kJ mol–1 2. –212.27 kJ mol–1
3. –212.27 J mol–1 4. –200.27 J mol–1
Subtopic:  Relation between Emf, G, Kc & pH |
 82%
Level 1: 80%+
NEET - 2022
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Given the following cell reaction:
 \(\mathrm{2Fe^{3+}(aq) \ + \ 2I^{-}(aq)\rightarrow 2Fe^{2+}(aq) \ + \ I_{2}(aq)}\)

  \(E_{cell}^{o} \ = \ 0.24 \ V\) at \(298\) \(K\).
The standard Gibbs energy ∆rG of the cell reaction is:

[Given: \(F  = 96500\) \(C\) \(mol^{- 1}\)]

1. \(23 . 16\) \(kJ\) \(mol^{- 1}\)

2. \(- 46 . 32\) \(kJ\) \(mol^{- 1}\)

3. \(- 23 . 16\) \(kJ\) \(mol^{- 1}\)

4. \(46 . 32\) \(kJ\) \(mol^{- 1}\)

Subtopic:  Relation between Emf, G, Kc & pH |
 75%
Level 2: 60%+
NEET - 2019
Hints

For a cell involving one electron \(E_{cell}^{\ominus} = 0 . 59  V\) at 298 K. The equilibrium constant for the cell reaction is :
\(\mathrm{[Given~ that~ \frac {2.303 ~RT}{F} = 0.059 ~V~ at~ T = 298 K]}\)

1. \(1 . 0 \times \left(10\right)^{30}\) 2. \(1 . 0 \times \left(10\right)^{2}\)
3. \(1 . 0 \times \left(10\right)^{5}\) 4. \(1 . 0 \times \left(10\right)^{10}\)

Subtopic:  Relation between Emf, G, Kc & pH |
 73%
Level 2: 60%+
NEET - 2019
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