What mass of glucose (C₆H₁₂O₆) must be dissolved in 1 liter of solution to make it isotonic with a 15 g/L solution of urea (NH₂CONH₂)?

The following solutions were prepared by dissolving 10 g of glucose (C₆H₁₂O₆) in 250 ml of water (P₁), 10 g of urea (CH₄N₂O) in 250 ml of water (P₂) and 10 g of sucrose (C₁₂H₂₂O₁₁) in 250 ml of water (P₃). The decreasing order of osmotic pressures of these solutions is:

Isotonic solutions have the same:

1. Vapour pressure

2. Freezing temperature

3. Osmotic pressure

4. Boiling temperature

200 mL of an aqueous solution contains 1.26 g of protein. The osmotic pressure of this solution at 300 K is found to be 2.57 × 10^–3 bar. The molar mass of protein will be:

(R = 0.083 L bar mol^–1 K^–1):

During osmosis, the flow of water through a semi-permeable membrane is:

A solution contains a non-volatile solute of molecular mass M₂. The molecular mass of solute in terms of osmotic pressure is:
where:

m₂ → Mass of solute

V → Volume of solution

\(\pi\) → Osmotic pressure

1. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{\pi }}\right)\mathrm{VRT}$

2. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{V}}\right)\frac{\mathrm{RT}}{\mathrm{\pi }}$

3. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{V}}\right)\mathrm{\pi RT}$

4. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{V}}\right)\frac{\mathrm{\pi }}{\mathrm{RT}}$

Which colligative property provides the most accurate method for determining the molecular weight of proteins and polymers?

1. Osmotic pressure

2. Lowering of vapour pressure 

3. Lowering of freezing point

4. Elevation in boiling point

1 % (w/w) solution of a compound is isotonic with 5 % (w/w) sucrose (sugar) solution. The molecular weight of the compound will be: