- 1(current)
Q. No.Given below are two statements:
| Assertion (A): | All the carbon atoms in H 2 C = C = CH 2 are sp2-hybridised. |
| Reason (R): | In this molecule, all the carbon atoms are attached to each other by double bonds. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Correct statement among the following is -
| a. | The hybridization of carbon in H2C=O is sp2 and shape is trigonal planar. |
| b. | The hybridization of carbon in CH3F is sp3 and shape is tetrahedral. |
| c. | The hybridization of carbon in HC≡N is sp and shape is linear. |
| 1. | Only a and b statements are correct. |
| 2. | Only b and c statements are correct. |
| 3. | All statements are correct. |
| 4. | None of the statements are correct. |
a. HC≡CCH=CHCH3 contains 10 σ bonds and 3 π bonds.
b. CH2=C=CHCH3 contains 7 σ bonds and 2 π bonds.
Correct among the above mentioned statement is -
1. Only statement 'a' is true.
2. Only statement 'b' is true
3. Both statements are true
4. Both statements are false
Match the terms mentioned in Column I with the terms in Column II.
|
Column I |
Column II |
|
A. Carbocation |
1. Species that can receive a pair of electrons |
|
B. Nucleophile |
2. Conjunction of electrons of bond with the empty p-orbital present in adjacent positively charged carbon |
|
C. Hyperconjugation |
3. hybridised carbon with empty p-orbital |
|
D. Electrophile |
4. Species that can donate a pair of electrons |
Codes
| Options: | A | B | C | D |
| 1. | 3 | 4 | 2 | 1 |
| 2. | 1 | 2 | 3 | 4 |
| 3. | 1 | 4 | 3 | 2 |
| 4. | 4 | 1 | 3 | 2 |
- 1(current)
Q. No.
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