Given below are two statements:
Assertion (A): | All the carbon atoms in H2C = C = CH2 are sp2-hybridised. |
Reason (R): | In this molecule, all the carbon atoms are attached to each other by double bonds. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
Correct statement among the following is:
a. | The hybridization of carbon in H2C=O is sp2 and shape is trigonal planar. |
b. | The hybridization of carbon in CH3F is sp3 and shape is tetrahedral. |
c. | The hybridization of carbon in HC≡N is sp and shape is linear. |
1. | Only a and b statements are correct. |
2. | Only b and c statements are correct. |
3. | All statements are correct. |
4. | None of the statements are correct. |
a. | HC≡CCH=CHCH3 contains 10 σ bonds and 3 π bonds. |
b. | CH2=C=CHCH3 contains 7 σ bonds and 2 π bonds. |
1. Only statement 'a' is true.
2. Only statement 'b' is true
3. Both statements are true
4. Both statements are false
Match the terms mentioned in Column-I with the terms in Column-II.
Column-I (Term) | Column-II (Definition) | ||
A. | Carbocation | (i) | Species that can receive a pair of electrons. |
B. | Nucleophile | (ii) | Conjunction of electrons of \(C-H ~\sigma-\) bond with the empty p-orbital present in adjacent positively charged carbon. |
C. | Hyperconjugation | (iii) | sp2 hybridised carbon with empty p-orbital. |
D. | Electrophile | (iv) | Species that can donate a pair of electrons. |
Options: | A | B | C | D |
1. | (iii) | (iv) | (ii) | (i) |
2. | (i) | (ii) | (iii) | (iv) |
3. | (i) | (iv) | (iii) | (ii) |
4. | (iv) | (i) | (iii) | (ii) |