# The number of σ and π bonds in the molecule ${C}_{6}{H}_{6}$ are - 1. 6 C – C sigma ( σ C - C )  bonds, 5 C–H sigma ( ( σ C - H )  bonds, and 3 C=C pi ( π C - C )  2. 6 C – C sigma ( σ C - C )  bonds, 5 C–H sigma ( ( σ C - H )  bonds, and 2 C=C pi ( π C - C )  3. 6 C – C sigma ( σ C - C )  bonds, 6 C–H sigma ( ( σ C - H )  bonds, and 3 C=C pi ( π C - C )  4. 6 C – C sigma ( σ C - C )  bonds, 6 C–H sigma ( ( σ C - H )  bonds, and 2 C=C pi ( π C - C )

Subtopic:  Hybridisation & Structure of Carbon Compounds |
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The number of σ and π bonds in the molecule ${C}_{6}{H}_{12}$ are:

1. 7 = (${\sigma }_{C-C}\right)$ , 11 =  $\left({\sigma }_{C-H}\right)$, and 0= π

2. 6 = (${\sigma }_{C-C}\right)$ , 12 =  $\left({\sigma }_{C-H}\right)$, and 0= π

3. 12 = (${\sigma }_{C-C}\right)$ , 6 =  $\left({\sigma }_{C-H}\right)$, and 1= π

4. 5 = (${\sigma }_{C-C}\right)$ , 13 =  $\left({\sigma }_{C-H}\right)$, and 1= π

Subtopic:  Hybridisation & Structure of Carbon Compounds |
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The number of σ and π bonds in the molecule ${\mathrm{CH}}_{2}{\mathrm{Cl}}_{2}$ are -

1.  2 = (${\sigma }_{C-Cl}\right)$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

2. 2 = (${\sigma }_{C-Cl}\right)$ , 2= $\left({\sigma }_{C-H}\right)$ , and 0= π

3. 2 = (${\sigma }_{C-Cl}\right)$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

4. 2 = (${\sigma }_{C-Cl}\right)$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

Subtopic:  Hybridisation & Structure of Carbon Compounds |
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Chlorine atom can be classified as:

 1 Carbocation 2 Nucleophile 3 Electrophile 4 Carbanion
Subtopic:  Nucleophile & Electrophile |
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$\stackrel{1}{C}{H}_{2}$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are -

 1 C1= sp , C2= sp3 2 C1= sp2 , C2= sp 3 C1= sp3 , C2= sp 4 C1= sp , C2= sp2
Subtopic:  Hybridisation & Structure of Carbon Compounds |
91%
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The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are - $2H=\stackrel{3}{C}{H}_{2}$

 1 C1= sp , C2= sp3 , C3= sp2 2 C1= sp2 , C2= sp3 , C3= sp3 3 C1= sp3 , C2= sp2 , C3= sp2 4 C1= sp3 , C2= sp3 , C3= sp3
Subtopic:  Hybridisation & Structure of Carbon Compounds |
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The correct hybridization states of carbon atoms in the following compound are -

 1 C1= sp , C2= sp3 , C3= sp2 2 C1= sp2 , C2= sp3 ,  C 3 = sp3 3 C1= sp2 , C2= sp2 ,  C 3 = sp 4 C1= sp3 , C2= sp3 ,  C 3 = sp3
Subtopic:  Hybridisation & Structure of Carbon Compounds |
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The correct hybridization states of carbon atoms in C6His/are:

1.  sp

2. sp

3. sp3

4.  All of the above

Subtopic:  Hybridisation & Structure of Carbon Compounds |
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During estimation of nitrogen present in an organic compound, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M H2SO4. The percentage of nitrogen in the compound is-

1. 46.0 %

2. 51.0%

3. 56.0%

4. 49.0%

Subtopic:  Quantitative Analysis of Organic Compounds |
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In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. The percentage of sulphur in the compound is-

1. 39.10 %

2. 48.13 %

3. 42.10 %

4. 52. 43 %

Subtopic:  Qualitative Analysis of Organic Compounds |
63%
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