The correct hybridization states of carbon atoms in the following compound are -
1. C1= sp , C2= sp3 , C3= sp2
2. C1= sp2 , C2= sp3 , = sp3
3. C1= sp2 , C2= sp2 , = sp
4. C1= sp3 , C2= sp3 , = sp3
The number of σ and π bonds in the molecule are -
1. 2 = ( , 1= , and 1= π
2. 2 = ( , 2= , and 0= π
3. 2 = ( , 1= , and 1= π
4. 2 = ( , 1= , and 1= π
The correct hybridization states of carbon atoms in the above compound are -
1. C1= sp , C2= sp3
2. C1= sp2 , C2= sp
3. C1= sp3 , C2= sp
4. C1= sp , C2= sp2
The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -
1. C1= sp , C2= sp3 , C3= sp2
2. C1= sp2 , C2= sp3 , C3= sp3
3. C1= sp3 , C2= sp2 , C3= sp2
4. C1= sp3 , C2= sp3 , C3= sp3
The number of σ and π bonds in the molecule are -
1. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
2. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
3. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
4. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
The number of primary carbon atoms in the following compound are-
1. 6
2. 2
3. 4
4. 3
The enolic form of ethyl acetoacetate is given below. The number of sigma and pi bonds in the enolic form of ethyl acetoacetate are -
1. 18 sigma bonds and 2 pi-bonds
2. 16 sigma bonds and 1 pi-bond
3. 9 sigma bonds and 2 pi-bonds
4. 9 sigma bonds and 1 pi-bond
The correct hybridization states of carbon atoms in C6H6 is/are:
1. sp2
2. sp
3. sp3
4. All of the above
The cylindrical shape of an alkyne is due to the presence of-
1. Three sigma C-C bonds
2. Three π C-C bonds
3. Two sigma C-C and one π C-C bonds
4. One sigma C-C and two π C-C bonds
The bond distance is longer in -
1.
2.
3.
4.