The reason why we fuse an organic compound with metallic sodium for testing nitrogen, sulphur, and halogens is -

1. To convert all compounds to their ionic form

2. Sodium reduces the compounds

3. Sodium converts all compounds in their covalent form

4. None of the above

0.3780 grams of an organic chloro compound gave 0.5740 grams of silver chloride in Carius
estimation. % of chlorine present in the compound is -

1. 25%

2. 37.59%

3. 42%

4. 05.70 %

In the Carius method, 0.468 grams of an organic sulphur compound gives 0.668 grams of barium sulphate.  The percentage of sulphur in the given compound is -

1. 19.59%

2. 25.40%

3. 09.24%

4. 27.59%

An organic compound contains 69% carbon, and 4.8% hydrogen, the remainder being
oxygen. The masses of carbon dioxide, and water produced when 0.20 g of this substance is subjected to complete combustion would be respectively -

1. 0.506 g , 0.0864 g

2. 0.906 g , 0.0864 g

3. 0.0506 g , 0.864 g

4. 0.0864 g, 0.506 g

A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 mL of 0.5 M ${\mathrm{H}}_2{\mathrm{SO}}_4$. The residual acid required 60 mL of 0.5 M solution of NaOH for neutralization. Percentage composition of nitrogen in the compound is -

1. 52%

2. 51%

3. 56 %

4. 54 %

A characteristic feature of any form of chromatography is the ___

1. Use of molecules that are soluble in water.

2. Use of inert carrier gas.

3. Calculation of an Rf value for the molecule separated.

4. Use of a mobile and a stationary phase.