The reason why we fuse an organic compound with metallic sodium for testing nitrogen, sulphur, and halogens is -

1. To convert all compounds to their ionic form

2. Sodium reduces the compounds

3. Sodium converts all compounds in their covalent form

4. None of the above

Subtopic:  Quantitative Analysis of Organic Compounds |
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0.3780 grams of an organic chloro compound gave 0.5740 grams of silver chloride in Carius
estimation. % of chlorine present in the compound is -

1. 25%

2. 37.59%

3. 42%

4. 05.70 %

Subtopic:  Quantitative Analysis of Organic Compounds |
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In the Carius method, 0.468 grams of an organic sulphur compound gives 0.668 grams of barium sulphate.  The percentage of sulphur in the given compound is -

1. 19.59%

2. 25.40%

3. 09.24%

4. 27.59%

Subtopic:  Quantitative Analysis of Organic Compounds |
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An organic compound contains 69% carbon, and 4.8% hydrogen, the remainder being
oxygen. The masses of carbon dioxide, and water produced when 0.20 g of this substance is subjected to complete combustion would be respectively -

1. 0.506 g , 0.0864 g

2. 0.906 g , 0.0864 g

3. 0.0506 g , 0.864 g

4. 0.0864 g, 0.506 g

Subtopic:  Quantitative Analysis of Organic Compounds |
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A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 mL of 0.5 M H2SO4. The residual acid required 60 mL of 0.5 M solution of NaOH for neutralization. Percentage composition of nitrogen in the compound is -

1. 52%

2. 51%

3. 56 %

4. 54 %

Subtopic:  Quantitative Analysis of Organic Compounds |
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A characteristic feature of any form of chromatography is the ___

1. Use of molecules that are soluble in water.

2. Use of inert carrier gas.

3. Calculation of an Rf value for the molecule separated.

4. Use of a mobile and a stationary phase.

Subtopic:  Quantitative Analysis of Organic Compounds |
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