Match the species given in Column I with the properties mentioned in Column II.

Column I	Column II
A.  \(\text{BF}^-_4\)	1. Oxidation state of the central atom is +4
B.  AlCl3	2. Tetrahedral shape
C.  SnO	3. Lewis acid
D.  PbO2	4. Can be further oxidized

Codes:

	A	B	C	D
1.	2	3	4	1
2.	1	2	3	4
3.	1	4	3	2
4.	4	1	3	2

Match the species given in Column I with properties given in Column II.

Given below are two statements: 

Given below are two statements: 

The correct order of ease of hydrolysis is-

1. CCl₄ < SiCl₄ < PCl₅ < AlCl₃

2. AlCl₃ < CCl₄ < PCl₅ < SiCl₄

3. CCl₄ < AlCl₃ < PCl₅ < SiCl₄

4. CCl₄ < AlCl₃ < SiCl₄ < PCl₅

Dry ice is -

1. Solid NH₃

2. Solid SO₂

3. Solid CO₂

4. Solid N₂

The reason behind carbon showing catenation property but lead does not is:

1. Due to the smaller size of C than that of Pb

2. Due to the smaller size of Pb than that of C

3. Due to the smaller ionization energy of C than that of Pb

4. Due to the inert pair effect

Identify the correct statements among the following:

1. (a) and (c) only

2. (b) and (c) only

3. (c) and (d) only

4. (a), (b) and (c) only

BCl₃  has higher stability than ${\mathrm{TlCl}}_3$, because -

Boron trifluoride behaves as a Lewis acid because -

1. Boron trifluoride is electron-rich.

2. Boron trifluoride is electron-deficient.

3. Boron trifluoride is highly stable.

4. None of these.