| 1. | H3BO3 | 2. | B2O3 |
| 3. | Na2B2O5 | 4. | NaB3O5 |
| List-I (Compounds) |
List-II (Molecular formula) |
||
| (a) | Borax | (i) | NaBO2+B2O3 |
| (b) | Kernite | (ii) | Na2B4O7.4H2O |
| (c) | Orthoboric acid | (iii) | H3BO3 |
| (d) | Borax bead | (iv) | Na2B4O7.10H2O |
| (a) | (b) | (c) | (d) | |
| 1. | (iv) | (ii) | (iii) | (i) |
| 2. | (ii) | (iv) | (iii) | (i) |
| 3. | (iii) | (i) | (iv) | (ii) |
| 4. | (i) | (iii) | (iv) | (ii) |
The chain length of silicones can be controlled by adding:
1. \(\mathrm{CH_3SiCl_3}\)
2. \(\mathrm{SiCl_4}\)
3. \(\mathrm{(CH_3)_2SiCl_2}\)
4. \(\mathrm{(CH_3)_3SiCl}\)
Which of the following is the correct statement?
1. Ga+ is more stable than ln+.
2. Al+ is more stable than ln+.
3. Ga+ is more stable than Al+.
4. Al+ is more stable than Ga+.
| 1. | Both diamond and graphite are used as dry lubricants. |
| 2. | Diamond and graphite have a two-dimensional network. |
| 3. | Diamond is covalent and graphite is ionic. |
| 4. | Diamond is sp³ hybridised and graphite is sp² hybridized. |
| 1. | Both the boron atoms are sp2 hybridised. |
| 2. | There are two 3-centre-2-electron bonds. |
| 3. | The four terminal B-H bonds are 2-centre-2-electron bonds. |
| 4. | The four terminal hydrogen atoms and the two boron atoms lie in one plane. |
Match the allotropes of cabon given in List I with the respective characteristics given in List II.
| List-I | List-II | ||
| A. | Coke | I. | Carbon atoms are sp3 hybridised. |
| B. | Diamond | II. | Used as a dry lubricant |
| C. | Fullerene | III. | Used as a reducing agent |
| D. | Graphite | IV. | Cage like molecules |
| Options: | (A) | (B) | (C) | (D) |
| 1. | III | IV | I | II |
| 2. | II | IV | I | III |
| 3. | IV | I | II | III |
| 4. | III | I | IV | II |
| 1. | Ga | 2. | In |
| 3. | Al | 4. | B |