In the given reaction,

xBrO3-+ yCr+3 + zH2$\to$Br2 + CrO42- + H+

The coefficients x, y, and z are respectively-

1. 6, 10, 11

2. 6, 10, 20

3. 6, 8, 22

4. 6, 10, 22

Subtopic:  Oxidizing & Reducing Agents | Balancing of Equations | Application of Electrode Potential |
59%
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Consider the given data:

${\mathrm{E}}_{{\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}}=0.77;$ ${\mathrm{E}}_{{\mathrm{I}}^{-}/{\mathrm{I}}_{2}}=$ $-0.54$
${\mathrm{E}}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}=0.80;$ ${\mathrm{E}}_{\mathrm{Cu}/{\mathrm{Cu}}^{2+}}=$ $-0.34$
${\mathrm{E}}_{{\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}}=0.77;$ ${\mathrm{E}}_{\mathrm{Cu}/{\mathrm{Cu}}^{2+}}=$ $-0.34$
${\mathrm{E}}_{\mathrm{Ag}/{\mathrm{Ag}}^{+}}=-0.80;$ ${\mathrm{E}}_{{\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}}=0.77$

Using the electrode potential values given above, identify the reaction which is not feasible:

 1 Fe3+(aq) and I- aq) 2 Ag+(aq) and Cu(s) 3 Fe3+(aq) and Cu(s) 4 Ag(s) and Fe3+(aq)

Subtopic:  Application of Electrode Potential |
61%
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In the following reaction

Al + Fe3O4 $\to$Al2O3 + Fe

The total number of electrons transferred will be-

1. 6

2. 8

3. 8/3

4. 24

Subtopic:  Application of Electrode Potential |
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