The oxidation number of carbon in C3O2  and Mg2C3 are respectively:

1. -4/3, +4/3

2. +4/3, -4/3

3. -2/3, +2/3

4. -2/3, +4/3

Subtopic:  Oxidizing & Reducing Agents |
89%
From NCERT
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Among the following the correct order of acidity is-

1. HClO < HClO2< HClO3< HClO4
2. HClO2< HClO < HClO3< HClO4
3. HClO4< HClO2< HClO < HClO3
4. HClO3< HClO4< HClO2< HClO

Subtopic:  Oxidizing & Reducing Agents |
85%
From NCERT
NEET - 2016
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The correct statement(s) about the given reaction is -

$\stackrel{}{\mathrm{X}}{\mathrm{eO}}_{6\left(\mathrm{aq}\right)}^{4-}+2{{\mathrm{F}}^{-1}}_{\left(\mathrm{aq}\right)}+6{{\mathrm{H}}^{+}}_{\left(\mathrm{aq}\right)}\to$
$\stackrel{}{\mathrm{X}}{\mathrm{eO}}_{3\left(\mathrm{g}\right)}+{\stackrel{}{\mathrm{F}}}_{2\left(\mathrm{g}\right)}+3{\mathrm{H}}_{2}{\mathrm{O}}_{\left(\mathrm{l}\right)}$

1. ${\mathrm{XeO}}_{6}^{4-}$ oxidises F-

2. The oxidation number of F increases from -1  to  zero

3. ${\mathrm{XeO}}_{6}^{4-}$ is a stronger oxidizing agent that ${\mathrm{F}}^{-}$

4. All of the above.

Subtopic:  Introduction to Redox and Oxidation Number | Oxidizing & Reducing Agents |
86%
From NCERT
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The element that does not show a disproportionation tendency is/are:

1. Cl

2. Br

3. F

4. I

Subtopic:  Oxidizing & Reducing Agents |
83%
From NCERT
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Oxidation number of oxygen in potassium super oxide (KO2) is-

1. – 2

2. – 1

3. – 1/2

4. – 1/4

Subtopic:  Oxidizing & Reducing Agents |
83%
From NCERT
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What is the alteration in the oxidation state of carbon in the given reaction?

$$\mathrm{{CH_4}_{(g)} + 4{Cl_2}_{(g)} \rightarrow {CCl_4}_{(l)} + 4 HCl_{(g)}}$$

1. 0 to +4

2. –4 to +4

3. 0 to –4

4. +4 to +4

Subtopic:  Oxidizing & Reducing Agents |
82%
From NCERT
NEET - 2020
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The oxidizing agent and reducing agent in the given reaction are :

$3{\mathrm{N}}_{2}{\mathrm{H}}_{4\left(\mathrm{l}\right)}+4{\mathrm{ClO}}_{3\left(\mathrm{aq}\right)}^{-}\to$
$6{\mathrm{NO}}_{\left(\mathrm{g}\right)}+4{\mathrm{Cl}}_{\left(\mathrm{aq}\right)}^{-}+6{\mathrm{H}}_{2}{\mathrm{O}}_{\left(\mathrm{l}\right)}$

1. Oxidising agent = ${\mathrm{N}}_{2}{\mathrm{H}}_{4}$; Reducing agent = ${\mathrm{ClO}}_{3}^{-}$

2. Oxidising agent = ${\mathrm{ClO}}_{3}^{-}$; Reducing agent = ${\mathrm{N}}_{2}{\mathrm{H}}_{4}$

3. Oxidising agent = ${\mathrm{N}}_{2}{\mathrm{H}}_{4}$ ; Reducing agent = ${\mathrm{N}}_{2}{\mathrm{H}}_{4}$

4. Oxidising agent = ${\mathrm{ClO}}_{3}^{-}$ ; Reducing agent = ${\mathrm{ClO}}_{3}^{-}$

Subtopic:  Oxidizing & Reducing Agents |
83%
From NCERT
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The oxidising agent and reducing agent in the given reaction are :

${}_{}$${\mathrm{Cl}}_{2}{\mathrm{O}}_{7\left(\mathrm{g}\right)}+4{\mathrm{H}}_{2}{\mathrm{O}}_{2\left(\mathrm{aq}\right)}+2{\mathrm{OH}}_{\left(\mathrm{aq}\right)}^{-}\to$
$2{\mathrm{ClO}}_{2\left(\mathrm{aq}\right)}^{-}+4{\mathrm{O}}_{2\left(\mathrm{g}\right)}+5{\mathrm{H}}_{2}{\mathrm{O}}_{\left(\mathrm{l}\right)}$${}_{}$

1. Oxidizing agent = H2O2; Reducing agent = ${\mathrm{Cl}}_{2}{\mathrm{O}}_{7}$

2. Oxidizing agent = ${\mathrm{Cl}}_{2}{\mathrm{O}}_{7}$; Reducing agent = ${\mathrm{H}}_{2}{\mathrm{O}}_{2}$

3. Oxidizing agent = H2O2; Reducing agent = H2O2

4. None of the above

Subtopic:  Oxidizing & Reducing Agents |
80%
From NCERT
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The incorrect statement regarding the rule to find the oxidation number among the following is-

 1 The oxidation number of hydrogen is always +1. 2 The algebraic sum of all the oxidation numbers carried by elements in a compound is zero. 3 An element in its free or uncombined state has an oxidation number of zero. 4 Generally, in all its compounds, the oxidation number of fluorine is -1.

Subtopic:  Oxidizing & Reducing Agents |
77%
From NCERT
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The change in oxidation number of chlorine when Cl2 gas reacts with hot and concentrated sodium hydroxide solution is:

1. Zero to +1 and Zero to –5

2. Zero to –1 and Zero to +5

3. Zero to –1 and Zero to +3

4. Zero to +1 and Zero to –3

Subtopic:  Oxidizing & Reducing Agents |
69%
From NCERT
AIPMT - 2012
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