- 1(current)
Q. No.Consider the following equation:
\(\small[Cr_2O^{2-}_7 (aq) + 3SO^{2-}_3 (aq) + 8H^+(aq) \rightarrow A + B + 4H_2O(l)\)
The product A and B are, respectively:
1. \(2 \mathrm{Cr}^{2+} ; 3 \mathrm{SO}_2 \)
2. \(2 \mathrm{Cr}^{+} ; \mathrm{S}_2 \mathrm{O}_7{ }^{2-} \)
3. \(2 \mathrm{Cr}^{3+} ; 3 \mathrm{SO}_4{ }^{2-} \)
4. \(2 \mathrm{Cr}^{3+} ; 3 \mathrm{HSO}_4{ }^{-}\)
Subtopic: Balancing of Equations |
80%
Level 1: 80%+
Hints
aMnO4–(aq) + bBr–(aq) + cH2O(l) → dMnO2(s) + eBrO3– (aq) + fOH–(aq)
The value of c, d and f in the above mentioned reaction are respectively:
The value of c, d and f in the above mentioned reaction are respectively:
| 1. | c = 1; d = 2; f = 2 | 2. | c = 2; d = 1; f = 2 |
| 3. | c = 2; d = 2; f = 1 | 4. | c = 1; d = 1; f = 1 |
Subtopic: Balancing of Equations |
66%
Level 2: 60%+
Hints
Permanganate(VII) ion, MnO4– in basic solution oxidizes iodide ion, I– to produce molecular iodine (I2) and manganese (IV) oxide (MnO2). The reaction is as follows:
aI–(aq) + bMnO4–(aq) + cH2O(l) → dI2(s) + eMnO2(s) + fOH–(aq)
The value of b, d and f are-
| 1. | b = 2; d = 3; f = 8 | 2. | b = 1; d = 3; f = 8 |
| 3. | b = 3; d = 8; f = 2 | 4. | b = 8; d = 3; f = 2 |
Subtopic: Balancing of Equations |
65%
Level 2: 60%+
Hints
Consider the following reaction:
Pb3O4 + 4HNO3 → A + B + 2H2O
A and B are respectively-
1. A=Pb(NO3)4; B=PbO2
2. A=Pb; B=O2
3. A= Pb(NO3)2; B=PbO2
4. A=PbO; B=NO2
Pb3O4 + 4HNO3 → A + B + 2H2O
A and B are respectively-
1. A=Pb(NO3)4; B=PbO2
2. A=Pb; B=O2
3. A= Pb(NO3)2; B=PbO2
4. A=PbO; B=NO2
Subtopic: Oxidizing & Reducing Agents | Balancing of Equations |
60%
Level 2: 60%+
Hints
- 1(current)
Q. No.
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