- 1(current)
Q. No.The incorrect statements among the following are-
| (a) | NaCl being an ionic compound is a good conductor of electricity in the solid-state |
| (b) | In canonical structure, there is a difference in the arrangement of atoms |
| (c) | Hybrid orbitals form stronger bonds than pure orbitals |
| (d) | VSEPR theory can explain the square planar geometry of XeF4 |
| 1. | (a) and (b) only | 2. | (b) and (c) only |
| 3. | (c) and (d) only | 4. | (b) and (d) only |
Subtopic: Resonance & Nature of Compounds | V.S.E.P.R & V.B.T |
69%
From NCERT
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh
Identify the incorrect statements, regarding the molecule XeO4:
1. XeO4 molecule is square planar
2. There are four p\(\pi\) – d\(\pi\) bonds
3. There are four sp3 – p, \(\sigma\) bonds
4. XeO4 molecule is tetrahedral
1. XeO4 molecule is square planar
2. There are four p\(\pi\) – d\(\pi\) bonds
3. There are four sp3 – p, \(\sigma\) bonds
4. XeO4 molecule is tetrahedral
Subtopic: V.S.E.P.R & V.B.T |
67%
From NCERT
NEET - 2013
Please attempt this question first.
Hints
Please attempt this question first.
Match List - I with List - II
| List - I | List - II | ||
| (a) | (i) | Square pyramidal | |
| (b) | (ii) | Trigonal planar | |
| (c) | (iii) | Octahedral | |
| (d) | (iv) | Trigonal bipyramidal |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (iii) | (i) | (iv) | (ii) |
| 2. | (iv) | (iii) | (ii) | (i) |
| 3. | (iv) | (iii) | (i) | (ii) |
| 4. | (ii) | (iii) | (iv) | (i) |
Subtopic: V.S.E.P.R & V.B.T |
78%
From NCERT
NEET - 2021
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
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NEET 2023 - Target Batch - Aryan Raj Singh
An incorrect statement among the following:
| 1. | The H-O-H bond angle in H2O is larger than the H-C-H bond angle in CH4 |
| 2. | The H-C-H bond angle in CH4 is larger than the H-N-H bond angle in NH3 |
| 3. | The H-C-H bond angle in CH4, the H-N-H bond angle in NH3 and the H-0-H bond angle in H2O are all greater than 90o |
| 4. | The H-O-H bond angle in H2O is smaller than the H-N-H bond angle in NH3 |
Subtopic: Hybridisation | V.S.E.P.R & V.B.T |
73%
From NCERT
NEET - 2016
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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