- 1(current)
Q. No.Match the species in Column I with the type of hybrid orbitals in Column II.
|
Column I |
Column II |
|
A. SF4 |
1. sp3d2 |
|
B. IF5 |
2. d2sp3 |
|
C. NO2+ |
3. sp3d |
|
D. NH4+ |
4. sp3 |
|
5. sp |
Codes
| Options: | A | B | C | D |
| 1. | 3 | 1 | 5 | 4 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match the species in Column I with the shape in Column II.
|
Column I |
Column II |
|
A. H3O+ |
1. Linear |
|
B. HCCH |
2. Angular |
|
C. ClO2- |
3. Tetrahedral |
|
D. NH4+ |
4. Trigonal bipyramidal |
|
5. Pyramidal |
Codes
| Options: | A | B | C | D |
| 1. | 5 | 1 | 2 | 3 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Given below are two statements:
| Assertion (A): | Though the central atom of both NH3 and H2O molecules are sp3 hybridised, yet H-N-H bond angle is greater than that of H-O-H. |
| Reason (R): | This is because nitrogen atom has one lone pair and oxygen atom has two lone pairs. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Which of the following attain the linear structure?
(a)
(b)
(c)
(d)
Choose the correct option
1. (a), (d)
2. (b), (c)
3. (c), (d)
4. (b), (d)
Which of the following species have the same shape?
(a) CO2
(b) CCl4
(c) O3
(d) NO2-
Choose the correct option
1. (a), (b)
2. (b), (c)
3. (c), (d)
4. (b), (d)
Among the following, the correct statements about
| a. |
The hybridisation of the central atom is sp3 |
| b. |
Its resonance structure has one C-O single bond and two C=O double bonds |
| c. |
The average formal charge on each oxygen atom is 0.67 units |
| d. |
All C-O bond lengths are equal |
Choose the correct option
1. (a), (b)
2. (b), (c)
3. (c), (d)
4. (b), (d)
The incorrect statements among the following are-
| 1. | NaCl being an ionic compound is a good conductor of electricity in the solid-state |
| 2. | In canonical structure, there is a difference in the arrangement of atoms |
| 3. | Hybrid orbitals form stronger bonds than pure orbitals |
| 4. | VSEPR theory can explain the square planar geometry of XeF4 |
1. (a), (b)
2. (b), (c)
3. (c), (d)
4. (b), (d)
- 1(current)
Q. No.
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