- 1(current)
Q. No.The number of bonds and bonds in the following structure is :
| 1. | 6, 19 | 2. | 4, 20 |
| 3. | 5, 19 | 4. | 5, 20 |
The electronic configurations of three elements, A, B, and C are given below.
A. 1s2 2s2 2p6
B. 1s2 2s2 2p6 3s2 3p3
C. 1s2 2s2 2p6 3s2 3p5
The molecular formula of the compound formed from B and C will be:
1.
2.
3.
4.
Match the items given in Column I with examples given in Column II.
|
Column I |
Column II |
||
| A. |
Hydrogen bond |
1. |
C |
| B. |
Resonance |
2. |
LiF |
| C. |
Ionic solid |
3. |
H2 |
| D. |
Covalent solid |
4. |
HF |
| 5. |
O3 |
Codes:
| Options: | A | B | C | D |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 2 | 1 |
Among the following, the correct statements about
| (a) |
The hybridisation of the central atom is sp3. |
| (b) |
Its resonance structure has one C-O single bond and two C=O double bonds. |
| (c) |
The average formal charge on each oxygen atom is 0.67 units. |
| (d) |
All C-O bond lengths are equal. |
Choose the correct option :
| 1. | (a), (b) | 2. | (b), (c) |
| 3. | (c), (d) | 4. | (b), (d) |
The incorrect statements among the following are-
| (a) | NaCl being an ionic compound is a good conductor of electricity in the solid-state |
| (b) | In canonical structure, there is a difference in the arrangement of atoms |
| (c) | Hybrid orbitals form stronger bonds than pure orbitals |
| (d) | VSEPR theory can explain the square planar geometry of XeF4 |
| 1. | (a) and (b) only | 2. | (b) and (c) only |
| 3. | (c) and (d) only | 4. | (b) and (d) only |
- 1(current)
Q. No.
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