If the electronic configuration of an element is 1s22s22p63s23p63d24s2, the four electrons that participate in the chemical bond formation will be from :

1. 3p6

2. 3p6, 4s2

3. 3p6, 3d2

4. 3d2, 4s2

Subtopic:  Covalent Bond |
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The correct bond angle for \(\mathrm{sp}^2\) hybridization is:

1. \(90^\circ\) 2. \(120^\circ\)
3. \(180^\circ\) 4. \(109^\circ\)
Subtopic:  Hybridisation |
 88%
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The electronic configurations of the elements A, B, and C are given below.

A  = 1s2  2s2  2p6
B  = 1s2  2s2  2p6  3s2  3p3
C =  1s2  2s2  2p6  3s2  3p5

The stable form of A may be represented by the formula:

1. A 2. A2
3. A3 4. A4
Subtopic:  Covalent Bond |
 81%
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The electronic configurations of the elements A, B, and C are given below.

A  = 1s2  2s2  2p6
B  = 1s2  2s2  2p6  3s2  3p3
C =  1s2  2s2  2p6  3s2  3p5

The stable form of C may be represented by the formula : 

1. C 2. C2
3. C3 4. C4
Subtopic:  Covalent Bond |
 78%
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The electronic configurations of three elements, A, B, and C are given below.  

A 1s2 2s2 2p6
B 1s2 2s2 2p6 3s2 3p3
C 1s2 2s2 2p6 3s2 3p5

The molecular formula of the compound formed from B and C will be 

1. BC

2. B2C

3. BC2

4. BC5

Subtopic:  Resonance & Nature of Compounds |
 54%
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The electronic configurations of the elements A, B, and C are given below.

A  = 1s2  2s2  2p6
B  = 1s2  2s2  2p6  3s2  3p3
C =  1s2  2s2  2p6  3s2  3p5

The bond between B and C will be : 

1. Ionic. 2. Covalent.
3. Hydrogen. 4. Coordinate.
Subtopic:  Covalent Bond |
 77%
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Among the following, the correct order of energies of molecular orbitals of N2 is-

1. (π2py)<(σ2pz)<(π*2px)(π*2py)

2. (π2py)>(σ2pz)>(π*2px)(π*2py)

3. (π2py)<(σ2pz) (π*2px)(π*2py)

4. (π2py)>(σ2pz)<(π*2px)(π*2py)

Subtopic:  M.O.T |
 67%
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From the perspective of molecular orbital theory, which statement is false?

1. Be2 is not a stable molecule.

2. He2 is not stable but He2+ is expected to exist.

3. Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.

4. The order of energies of molecular orbitals in N2 molecule is: 

σ2s<σ2s*<σ2pz<(π2pxπ2py)
<(π2px*π2py*)<σ2pz*

Subtopic:  M.O.T |
 75%
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What is the correct sequence of bond order for the specified species?

1. \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2\) 2. \(\mathrm{O}^-_2<\mathrm{O}_2<\mathrm{O}^+_2\)
3. \(\mathrm{O}^-_2>\mathrm{O}_2<\mathrm{O}^+_2\) 4. \(\mathrm{O}^-_2<\mathrm{O}_2>\mathrm{O}^+_2\)
Subtopic:  M.O.T |
 83%
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Match the species in Column I with the type of hybrid orbitals in Column II.

Column I

Column II

A. SF4

1. sp3d2

B. IF5

2. d2sp3

C. NO2+

3. sp3d

D. NH4+

4. sp3

5. sp

Codes

Options:  A   B   C   D 
1. 3 1 5 4
2. 1 2 3 5
3. 5 4 3 2
4. 4 5 3 2

       

Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
 88%
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