Lewis symbols for the atoms and ions: S and S^2–; Al and Al³⁺; H and H^– respectively, would be:

1.
2.
3.
4.

Which of the following factors are favourable for the formation of an ionic bond?

The correct relationship between bond strength and bond order is :

The bond length can be defined as -

${\mathrm{}}_{}{\mathrm{}}_{}$\(\text{H}_3\text{PO}_3\) can be represented by structures 1 and 2 shown below.

However, these two structures cannot be considered as canonical forms of a resonance hybrid because:

The shape of ${\mathrm{H}}_2\mathrm{O}$ molecule is bent while that of ${\mathrm{CO}}_2$ is linear. The correct explanation for this fact is that dipole moment of:

The application of dipole moment is/are :

The difference between electronegativity and electron gain enthalpy is:

The correct order of increasing ionic character in the molecules: LiF, K₂O, ${\mathrm{N}}_2, {\mathrm{SO}}_2$ and ClF₃ is:

1. ${\mathrm{N}}_2 < {\mathrm{ClF}}_3 < {\mathrm{SO}}_2< {\mathrm{K}}_2\mathrm{O} < \mathrm{LiF}$

2. ${\mathrm{N}}_2 < {\mathrm{ClF}}_3 < \mathrm{LiF} < {\mathrm{SO}}_2< {\mathrm{K}}_2\mathrm{O}$

3. ${\mathrm{SO}}_2< {\mathrm{K}}_2\mathrm{O} < {\mathrm{ClF}}_3 < \mathrm{LiF} < {\mathrm{N}}_2$

4. ${\mathrm{N}}_2 < {\mathrm{SO}}_2 < {\mathrm{ClF}}_3 < {\mathrm{K}}_2\mathrm{O} < \mathrm{LiF}$

CH₄ does not exhibit square planar geometry because: