The relative order of stability of the following species: \(\mathrm{O}_2,\mathrm{O}^+_2,\mathrm{O}^-_2~\mathrm{and}~\mathrm{O}^{2-}_2\) is -
1. | \(\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) | 2. | \(\mathrm{O}^{2-}_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\) |
3. | \(\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) | 4. | \(\mathrm{O}_2>\mathrm{O}^{2-}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\) |
The plus and negative sign of the orbitals mean:
1. Wave function.
2. Probability density.
3. Quantum number of orbitals.
4. Frequency of orbitals.
In the option are given sequences of increasing bond order for the following species. The correct option is :
\(\mathrm{O}_2,\mathrm{N}_2,\mathrm{O}^+_2 ~\mathrm{and}~\mathrm{O}^-_2\)
1. | \(\mathrm{O}_2>\mathrm{N}_2>\mathrm{O}^+_2>\mathrm{O}^-_2\) | 2. | \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{N}_2\) |
3. | \(\mathrm{N}_2>\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2\) | 4. | \(\mathrm{O}^-_2>\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{N}_2\) |
The change in the hybridization of the Al atom in the above reaction is:
1. \(s p^{2} \text { to } s p^{3}\)
2. \(\mathrm{sp}^{3} \text { to } s p^{2}\)
3. \(\mathrm{sp}^{3} \text { to } \mathrm{dsp}{ }^{2}\)
4. \(\operatorname{sp}^{2} \text { to } d s p^{2}\)
Considering the X-axis as the internuclear axis, a sigma bond will not be formed in:
The incorrect statement about NH3 and H2O is :
1. The bond angle in NH3 is less than in H2O.
2. Both have distorted tetrahedral geometries.
3. The bond angle in H2O is less than in NH3.
4. Both are sp3 hybridized.
The shape of AsF5 is:
1. Pentagonal bipyramidal.
2. Trigonal bipyramidal.
3. Distorted tetrahedral.
4. Square pyramidal.
The driving force of an atom to form chemical bonds involves:
1. To increase the size.
2. To decrease size.
3. To attain stability.
4. None of the above.
The Lewis dot symbols for atoms of the elements Mg, Na, O, and N, respectively, would be:
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Lewis symbols for the atoms and ions: S and S2–; Al and Al3+; H and H– respectively, would be:
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