Column-I (Compound) | Column-II Hybridisation | ||
(i) | \(PCl_5 \) | (a) | \(sp^3d^2 \) |
(ii) | \([Pt(CN)_4]^{-2} \) | (b) | \(sp^3d \) |
(iii) | \([Co(NH_3)_6]^{3+} \) | (c) | \(d^2sp^3 \) |
(iv) | \(BrF_5 \) | (d) | \(dsp^2 \) |
I | II | III | IV | |
1. | b | d | c | a |
2. | a | b | c | d |
3. | b | d | a | c |
4. | d | b | a | c |
1. | It has one lone pair at the equatorial position with two lone pair-bond pair repulsion at 90°. |
2. | It has one lone pair at the axial position with two lone pair-bond pair repulsion at 90°. |
3. | It has one lone pair at the equatorial position with three lone pair-bond pair repulsion at 90°. |
4. | It has one lone pair at the axial position with three lone pair-bond pair repulsion at 90°. |
In molecule, the hybridization of carbon 1,2,3 and 4 respectively are :
1.
2.
3.
4.
The molecule in which hybrid MOs involve only one d-orbital of the central atom is:
1. \(X e F_{4}\)
2. \(\left[ N i (CN)_{4} \right]^{2 -}\)
3. \(B r F_{5}\)
4. \(\left[ C r F_{6} \right]^{3 -}\)
The structure of PCl5 in the solid state is:
1. Square pyramidal.
2. Tetrahedral [PCl4]+ and octahedral [PCl6]–
3. Square planar [PCl4] and octahedral [PCl6]–
4. Trigonal bipyramidal.
The compound that has the largest H–M–H bond angle (M=N, O, S, C), is:
1. | H2O | 2. | CH4 |
3. | NH3 | 4. | H2S |
The ion that has sp3d2 hybridization for the central atom is:
1. [ICl4]–
2. [ICl2]–
3. [BrF2]–
4. [IF6]–
Total number of lone pair of electrons in \({I }_{3}^{-}\) ion are:
1. | 3 | 2. | 6 |
3. | 9 | 4. | 12 |
In which of the following pairs the two species are not isostructural?
1. PCl4+ and SiCl4
2. PF5 and BrF5
3. AlF63− and SF6
4. CO32− and NO3−
Which of the following compounds has the smallest bond angle?
1. SO2
2. H2O
3. H2S
4. NH3