Match Column I with Column II.
Column-I | Column-II | ||
(a) | Copper | (i) | Non-metal |
(b) | Fluorine | (ii) | Transition metal |
(c) | Silicon | (iii) | Lanthanoid |
(d) | Cerium | (iv) | Metalloid |
(a) | (b) | (c) | (d) | |
1. | (ii) | (iv) | (i) | (iii) |
2. | (ii) | (i) | (iv) | (iii) |
3. | (iv) | (iii) | (i) | (ii) |
4. | (i) | (ii) | (iii) | (iv) |
The maximum number of elements that can be accommodated in the sixth period are :
1. 8
2. 18
3. 32
4 16
The period and group number of the element with Z =114 are:
1. | 8th period and 16th group | 2. | 7th period and 14th group |
3. | 14th period and 7th group | 4. | 9th group and 14th period |
Elements with an electronic configuration 1s2 2s22p6 3s23p63d10 4s24p64d10 5s25p3 belong to the group :
1. | 3rd | 2. | 15th |
3. | 17th | 4. | 2nd |
The outermost electronic configuration of the most electronegative element is :
1. | \(ns^2,np^3\) | 2. | \(ns^2,np^6n-1d^5\) |
3. | \(ns^2,np^5\) | 4. | \(ns^2,np^6 \) |
Sodium generally does not show an oxidation state of +2, because of:
1. High first ionization potential.
2. High second ionization potential.
3. Large ionic radius.
4. High electronegativity.
The pair that has both members from the same period of the Periodic Table is
1. | Cl, Br | 2. | Ca, Cl |
3. | Na, Ca | 4. | Na, Cl |
The electronic configuration that represents the d-block element is:
1. 1s2 2s2 2p6 3s23p63d10 4s24p6
2. 1s2 2s2 2p6 3s23p63d10 4s24p1
3. 1s2 2s2 2p6 3s23p63d10 4s2
4. 1s2 2s2 3s23p6 4s2
The general outer electronic configuration of s, p, d , and f-block elements respectively would be :
1. | ns1-2, nd2np1-6, (n-1)d1-10np0-2, (n-2)f1-14(n-1)d0-10ns2 |
2. | ns1-2, ns2np1-6, (n-1)f1-10ns0-2, (n-2)g1-14(n-1)d0-1ns2 |
3. | ns1-2, ns2np1-6, (n-1)d1-10ns1-2, (n-2)f1-14(n-1)d0-1 ns2 |
4. | np1-2, nd2np1-6, (n-1)d1-10ns0-2, (n-2)f1-14(n-1)d0-10ns2 |
The electronic configuration of chalcogens in their outermost shell is :
1.
2.
3.
4.