The formation of the oxide ion O2- (g), from oxygen atom requires first an exothermic and then an endothermic step as shown below, 
 Og+e-O-; fH0=-141 KJ mol-1O-g+e-O2-g; fH0=+780 KJ mol-1
Thus, process of formation of O2- in gas phase is unfavorable even though O2- is isoelectronic with neon. It is due to the fact that :
1. Electron repulsion outweighs the stability gained by achieving  noble gas configuration .
2. O- ion has comparatively smaller size than oxygen atom.
3. Oxygen is more electronegative.
4. Addition of electron in oxygen result in large size of the ion .

Subtopic:  Electron Affinity (EA) |
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The species Ar, K+ and Ca2+ contain the same number of electrons. In which order do their radii increase?
1.  Ar < K< Ca2+
2. Ca2+ < Ar < K+
3. Ca2+ < K< Ar
4. K+ < Ar < Ca2+

Subtopic:  Atomic Size |
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Which of the following order of ionic radii is correctly represented?
1. H->H+>H 
2. Na+>F->O2-
3. F->O2->Na+
4. N3->Mg2+>Al3+

Subtopic:  Atomic Size |
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Be2+ is isoelectronic with which of the following ions?
1. H+
2. Li+
3. Na+
4. Mg2+

Subtopic:  Electronic Configuration |
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What is the value of electron gain enthalpy of Na+ if IE1 of Na = 5.1 eV?

1. + 10.2 eV 

2. –5.1 eV

3. –10.2 eV 

4. + 2.55 eV

Subtopic:  Electron Affinity (EA) |
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The correct order of the decreasing ionic radii among the following isoelectronic species is:

1. Ca2+>K+>S2->Cl-

2. Cl->S2->Ca2+>K+

3. S2->Cl->K+>Ca2+

4. K+>Ca2+>Cl->S2-

Subtopic:  Atomic Size |
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Which of the following represents the correct order of increasing electron affinity for the elements, O, S, F and Cl ?

1. Cl < F < O < S

2. O < S < F < Cl

3. F < S < O < Cl

4. S < O < Cl < F

Subtopic:  Electron Affinity (EA) |
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Among the elements Ca, Mg, P and Cl, the correct order of increasing atomic radii is -
1. Cl < P < Mg < Ca
2. P < Cl < Ca < Mg
3. Ca < Mg < P < Cl
4. Mg < Ca < Cl < P

Subtopic:  Atomic Size |
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Amongst the elements with following electronic configurations, which one of them may have the highest ionisation energy ?

1. [Ne] 3s2 3p3

2. [Ne] 3s2 3p2

3. [Ar] 3d10  4s2 4p3

4. [Ne] 3s2 3p1

Subtopic:  Ionization Energy (IE) | Electronic Configuration |
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The correct order of decreasing second ionization enthalpy of Ti(22), V(23), Cr (24) and Mn(25) is

1.  Cr > Mn > V > Ti

2.  V > Mn > Cr > Ti

3.  Mn > Cr > Ti > V

4.  Ti > V > Cr > Mn

Subtopic:  Ionization Energy (IE) |
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