The set of quantum numbers which represent 3p is
1. n =1, l =0;
2, n = 3; l=1
3. n = 4; l =2;
4. n = 4; l = 3 

Orbital that does not exist:

The possible values of n, l, and m for the electron present in 3d would be respectively:

1. n = 3, l = 1, m = – 2, – 1, 3, 1, 2

2. n = 3, l = 3, m = – 2, – 1, 0, 1, 2

3. n = 3, l = 2, m = – 2, – 1, 0, 1, 2

4. n = 5, l = 2, m = – 2, – 1, 0, 1, 2

A pair of d-orbitals having electron density along the axes is: 

1. $d_{z^2},$ $d_{xz}$

2. $d_{xz},$ $d_{zy}$

3. $d_{z^2},$ $d_{x^2-y^2}$

4. $d_{xy},$ $d_{x^2-y^2}$

The maximum number of electrons in a subshell with l = 3 and n = 4 is

1. 14

2. 16

3. 10

4. 12

The number of electrons that can be present in the subshells having m_s value of \(-\frac{1}{2}\) for n = 4 are:

1. 36

2. 4

3. 16

4. 2

The lowest value of n for 'g' orbitals is :
1. 4
2. 5
3. 3
4. 1

The number of electrons with the azimuthal quantum number l = 1 and 2 for Cr ₂₄ in ground state is

1. 16 and 5

2. 12 and 5

3. 16 and 4

4. 12 and 4

The rule used to determine the maximum number of electrons in a subshell of an atom is: