The transition in the hydrogen spectrum that would have the same wavelength as Balmer transition from n = 4 to n = 2 of He+ spectrum is -

1. n1 = 3 to n2 = 4

2. n2  = 3 to n1 = 2

3. n2  = 3 to n1 = 1

4. n2  = 2 to n1 = 1

Subtopic:  Hydrogen Spectra |
 64%
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2 ×108 atoms of carbon are arranged side by side. The radius of a carbon atom if the length of this arrangement is 2.4 cm would be 

1. 7.0 x 10-11 m

2. 5.0 x 10-11 m

3. 8.0 x 10-11 m

4. 6.0 x 10-11 m

Subtopic:  Introduction of Atomic Structure |
 71%
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The diameter of a zinc atom is 2.6 Å. If zinc atoms are arranged side by side lengthwise, number of atoms present in a length of 1.6 cm would be:

1. 5.153 x 107 2. 6.153 x 107
3. 4.153 x 109 4. 6.153 x 103
Subtopic:  Introduction of Atomic Structure |
 77%
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A certain particle carries 2.5 × 10–16 C of static electric charge. The number of electrons present in it would be:

1. 1460  2. 1350
3. 1560 4. 1660

Subtopic:  Introduction of Atomic Structure |
 75%
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In Rutherford's experiment, generally, the thin foil of heavy atoms like gold, platinum, etc. have been used to be bombarded by the α-particles.

 If the thin foil of light atoms like aluminum etc. is used in Rutherford’s experiment, the difference that would be observed from the above results is :

1. The same results will be observed.

2. More deflection would be observed.

3. There will not be enough deflection.

4. None of the above.

Subtopic:  Introduction of Atomic Structure |
 62%
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Symbols Br3579 and B79r can be written,
whereas symbols Br7935 and B35r are not acceptable because:

1. The general convention for representing an element along with its atomic number (A) and atomic mass (Z) is XZA
2. The general convention for representing an element along with its atomic mass (A) and atomic number (Z) is XZA
3. The general convention for representing an element along with its wavelength (A) and frequency (Z) is XZA
4. The general convention for representing an element along with its isotopes (A) and atomic number (Z) is XZA
Subtopic:  Introduction of Atomic Structure |
 81%
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The correct arrangement of the following electromagnetic spectrum in the increasing order of frequency is:

1. Cosmic rays < Amber light < Radiation of FM radio < X-rays < Radiation from microwave ovens
2. Radiation from FM radio  < Radiation from microwave oven < Amber light < X- rays < Cosmic rays
3. Radiation from microwave ovens < Amber light < Radiation of FM radio < X-rays < Cosmic rays
4. Cosmic rays < X-rays < Radiation from microwave ovens < Amber light < Radiation of FM radio

Subtopic:  Electromagnetic Radiation |
 69%
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The work function for the Cesium atom is \(1.9~\mathrm{eV}.\) The threshold frequency of the radiation is:

1. \(4.59 \times10^{14}~s^{-1}\) 2. \(8.59 \times10^{14}~s^{-1}\)
3. \(5.59 \times10^{-14}~s^{-1}\) 4. \(65.9 \times10^{14}~s^{-1}\)
Subtopic:  Photo Electric Effect |
 73%
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When a photon with a wavelength of 150 pm strikes an atom, one of its inner bound electrons is ejected at a velocity of 1.5 × 107 m s–1 The energy with which it is bound to the nucleus would be:

1. 32.22 × 10–16 J

2. 12.22 × 10–16 J

3. 22.27 × 10–16 J

4. 31.22 × 10–16 J
 

Subtopic:  Photo Electric Effect |
 70%
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If the position of the electron were measured with an accuracy of +0.002 nm, the uncertainty in the momentum of the electron would be: 

1. 5.637 × 10–23 kg m s–1

2. 4.637 × 10–23 kg m s–1

3. 2.637 × 10–23 kg m s–1

4. 3.637 × 10–23 kg m s–1

Subtopic:  Heisenberg Uncertainty Principle |
 72%
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