# The number of electrons in the species ${\mathrm{H}}_{2}^{+}$ $,$ ${\mathrm{H}}_{2}$ $,$ ${\mathrm{O}}_{2}^{+}$,  are respectively: 1. 15, 2, 1 2. 15, 1, 2 3. 1, 2, 15 4. 2, 1, 15

Subtopic:  Number of Electron, Proton & Neutron |
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Orbital that does not exist:

 1 6p 2 2s 3 3f 4 2p

Subtopic:  Shell & Subshell |
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The set of quantum numbers which represent 3p is
1. n =1, =0;
2, n
= 3; l=1
3. n
= 4; l =2;
4. n
= 4; = 3

Subtopic:  Shell & Subshell |
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Which of the following sets of quantum numbers is possible-
1. n
= 0, l = 0, ml = 0, ms = + ½
2. n
= 1, l = 0, ml = 0, ms = – ½
3. n
= 1, l = 1, ml = 0, ms = + ½
4. n
= 3, l = 3, ml = –3, ms = + ½

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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The total number of electrons in an atom with the following quantum numbers would be
(a) n = 4, ms = – ½  (b) n = 3, l = 0
1. 16,  2
2. 11, 8
3. 16, 8
4. 12, 7

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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The transition in the hydrogen spectrum that would have the same wavelength as Balmer transition from n = 4 to n = 2 of He+ spectrum is -

1. ${\mathrm{n}}_{1}$ $=$ $3$ $\mathrm{to}$ ${\mathrm{n}}_{2}$ $=$ $4$

2. ${\mathrm{n}}_{2}$  = 3 to n1 = 2

3. ${\mathrm{n}}_{2}$  = 3 to n1 = 1

4. ${\mathrm{n}}_{2}$  = 2 to n1 = 1

Subtopic:  Hydrogen Spectra |
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2 ×108 atoms of carbon are arranged side by side. The radius of a carbon atom if the length of this arrangement is 2.4 cm would be

1. 7.0 x 10-11 m

2. 5.0 x 10-11 m

3. 8.0 x 10-11 m

4. 6.0 x 10-11 m

Subtopic:  Introduction of Atomic Structure |
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The diameter of a zinc atom is 2.6 Å. If zinc atoms are arranged side by side lengthwise, number of atoms present in a length of 1.6 cm would be:

 1 5.153 x 107 2 6.153 x 107 3 4.153 x 109 4 6.153 x 103
Subtopic:  Introduction of Atomic Structure |
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A certain particle carries 2.5 × 10–16 C of static electric charge. The number of electrons present in it would be:

 1 1460 2 1350 3 1560 4 1660

Subtopic:  Introduction of Atomic Structure |
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In Rutherford's experiment, generally, the thin foil of heavy atoms like gold, platinum, etc. have been used to be bombarded by the α-particles.

If the thin foil of light atoms like aluminum etc. is used in Rutherford’s experiment, the difference that would be observed from the above results is :

1. The same results will be observed.

2. More deflection would be observed.

3. There will not be enough deflection.

4. None of the above.

Subtopic:  Introduction of Atomic Structure |
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