A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c=3.0×108 ms-1]

1. 2192 m

2. 21.92 cm

3. 219.3 m

4. 219.2 m

Subtopic:  Electromagnetic Radiation |
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The number of protons, neutrons and electrons in Lu71175, respectively, are:

1.  104, 71 and 71

2.  71, 71 and 104

3.  175, 104 and 71

4.  71, 104 and 71 

Subtopic:  Introduction of Atomic Structure | Number of Electron, Proton & Neutron |
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The number of angular nodes and radial nodes in 3s orbital are

1. 0 and 2, respectively

2. 1 and 0, respectively

3. 3 and 0, respectively

4. 0 and 1, respectively

Subtopic:  Nodal Plane |
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4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:

1.  5f>6p>4d>5p

2.  5f>6p>5p>4d

3.  6p>5f>5p>4d

4.  6p>5f>4d>5p

Subtopic:  AUFBAU Principle |
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Which of the following series of transitions in the spectrum of hydrogen atom falls in visible region?

1.  Brackett series

2.  Lyman series

3.  Balmer series

4.  Paschen series

Subtopic:  Hydrogen Spectra |
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Orbital having 3 angular node and 3 total nodes is:
1. 5 p
2. 3 d
3. 4 f
4. 6 d

Subtopic:  Nodal Plane |
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In hydrogen atom, what is the de Broglie wavelength of an electron in the second Bohr orbit is: [Given that Bohr radius, a0=52.9 pm]

(1) 211.6 pm

(2) 211.6 πpm

(3) 52.9 πpm

(4) 105.8 pm

Subtopic:  Bohr's Theory |
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If radius of second Bohr orbit of the \(He^+\) ion is 105.8 pm, what is the radius of third Bohr orbit of \(Li^{2+}\) ion? 
1. 158.7 Å
2. 158.7 pm 
3. 15.87 pm 
4. 1.587 pm
Subtopic:  Hydrogen Spectra |
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Which one of the following electrons in the ground state will have least amount of energy?
1. An electron in hydrogen atom.
2. An electron in 2p orbital of carbon atom.
3. The electron of copper atom present in 4s orbital.
4. The outermost electron in sodium atom.

Subtopic:  AUFBAU Principle |
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A monochromatic infrared range finder of power 1mW emits photons with wavelength 1000 nm in 0.1 second. The number of photons emitted in 0.1 second is-
(Given -h = \(6.626 \times 10^{-34} J~s\) , \(c = 3 \times 10^8 m~s^{-1}, \) Avogadro number = \(6.022 \times 10^{23}\))
1. \(30 \times 10^{37}\)
2. \(5 \times 10^{14} \)
3. \(30 \times 10^{34} \)
4. \(5 \times 10^{11} \)

Subtopic:  Electromagnetic Radiation |
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