The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is:

(Charge on electron = 1.60 × 10–19 C)

1.  6×1023

2.  6×1020

3.  3.75×1020

4.  7.48×1020

Subtopic:  Faraday’s Law of Electrolysis |
 80%
From NCERT
NEET - 2016
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The  number of electrons involved in the deposition of 63.5 g of Cu from a solution of CuSO4 is:

6.022 × 1023 

3.011 × 1023 

12.044 × 1023 

 6.022 × 1022

Subtopic:  Faraday’s Law of Electrolysis |
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Given below are two statements:
Statement I: \(2 \mathrm{~F}\) electricity is required for the oxidation of 1 mole \(\mathrm{H}_2 \mathrm{O}\) to \(\mathrm{O}_2\).
Statement II: To get \(40.0 \mathrm{~g}\) of Aluminium from molten \(\mathrm{Al}_2 \mathrm{O}_3\) required electricity is \(4.44 \mathrm{~F}\).

In the light of the above statements, choose the correct answer from the options given below:
1. Both Statement I and Statement II are true
2. Both Statement I and Statement II are false
3. Statement I is true but Statement II is false
4. Statement I is false but Statement II is true
Subtopic:  Faraday’s Law of Electrolysis |
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NEET - 2024
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When 0.1 mol MnO42– is oxidized, the quantity of electricity required to completely oxidise MnO42– to MnO4 is:

1. 96500 C

2. 2 × 96500 C

3. 9650 C

4. 96.50 C

Subtopic:  Faraday’s Law of Electrolysis |
 78%
From NCERT
AIPMT - 2014
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The weight of silver (at.wt. = 108) displaced by a quantity of electricity which displaces 5600 mL of Oat STP will be:

1. 5.4 g

2. 10.8 g

3. 54.0 g

4. 108.0 g

Subtopic:  Faraday’s Law of Electrolysis |
 56%
From NCERT
AIPMT - 2014
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Match the redox conversions in List-I with the corresponding number of Faradays required in List-II.
List-I
(Redox Conversion)
List-II
(Number of Faraday required)
A. 1 mol of H2O to O2 I. 3F
B. 1 mol of \(MnO^-_4\) to \(Mn^{2+}\) II. 2F
C. 1.5 mol of \(Ca\) from molten \(CaCl_2\) III. 1F
D. 1 mol of FeO to Fe2O3 IV. 5F
Choose the correct answer from the options given below:
1. A - III, B - IV, C - I, D - II
2. A - II, B - III, C - I, D - IV
3. A - III, B - IV, C - II, D - I
4. A - II, B - IV, C - I, D - III
Subtopic:  Faraday’s Law of Electrolysis |
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NEET - 2024
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For the cell, Ti/Ti+(0.001M)||Cu2+(0.1M)|Cu, Ecello at

25 °C is 0.83 V. Ecell can be increased :

1. By increasing [Cu2+]

2. By increasing [Ti+]

3. By decreasing [Cu2+]

4. None of the above.

Subtopic:  Nernst Equation | Faraday’s Law of Electrolysis |
 72%
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During the electrolysis of molten sodium chloride, the time required to produce 0.10 mol of chlorine gas using a current of 3 amperes is:

1. 55 minutes

2. 110 minutes

3. 220 minutes

4. 330 minutes

Subtopic:  Faraday’s Law of Electrolysis |
 56%
From NCERT
NEET - 2016
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The number of Faradays (F) required to produce 20 g of calcium from molten CaCl2 (Atomic mass of Ca = 40 g mol–1) is:

1. 2

2. 3

3. 4

4. 1

Subtopic:  Faraday’s Law of Electrolysis |
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NEET - 2020
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The same amount of electricity was passed through two cells containing molten Al2O3 and molten NaCl. If 1.8 g of Al were liberated in one cell, the amount of Na liberated in the other cell is:

1. 4.6 g

2. 2.3 g

3. 6.4 g

4. 3.2 g

Subtopic:  Faraday’s Law of Electrolysis |
 72%
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