Based on equation E = –2.178 × 10–18J, Z2n2 certain conclusions are written. Which of them is not correct?

1. Larger the value of n, the larger the orbit radius.
2. Equation can be used to calculate the change in energy when the electron changes orbit.
3. For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.
4. The negative sign in the equation simply means that the energy of the electron bound to the nucleus is lower than what it would be if the electrons were at an infinite distance from the nucleus.
Subtopic:  Bohr's Theory |
 67%
Level 2: 60%+
AIPMT - 2013
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The radii of the first bohr orbit of H(rH), He+ (rHe+) and Li2+(rLi2+) are in the order:

1.  rH = rHe= rLi+2

2.  rH < rHe+ < rLi2+

3.  rH > rHe+ > rLi2+

4.  rHe+ < rH < rLi2+

Subtopic:  Bohr's Theory |
 82%
Level 1: 80%+
Hints

Given below are two statements:
Assertion (A): Splitting of spectral lines under the influence of an electric field is known as the Stark effect.
Reason (R):  Bohr’s theory accounts for this splitting of spectral lines.
 
1.  Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True and (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Bohr's Theory |
 68%
Level 2: 60%+
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