The conductivity of 0.00241 M acetic acid is 7.896 × 10–5 S cm–1. If Λm0 for acetic acid is 390.5 S cm2 mol–1, the dissociation constant will be -

\(1. \ 2.45 \times 10^{-5} \mathrm{~mol} \ \mathrm{~L}^{-1} \\ 2. \ 1.86 \times 10^{-5} \mathrm{~mol} \ \mathrm{L^{-1}} \\ 3. \ 3.72 \times 10^{-5}\mathrm{~mol} \mathrm{~L^{-1}} \\ 4. \ 2.12 \times 10^{-5}\mathrm{~mol} \mathrm{~L^{-1}}\)

Subtopic:  Conductance & Conductivity |
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The resistance of a cell containing 0.001 M KCl solution at 298 K is 1500 . The conductivity is 0.146 × 10–3 S cm–1The cell constant would be-

1. 0.12 cm-1

2. 0.56 cm-1

3. 0.22 cm-1

4. 1.36 cm-1

Subtopic:   Kohlrausch Law & Cell Constant |
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The amount of charge required for the reduction of 1 mol of MnO4- to Mn2+ is -

1. 4.8 × 105 C
2. 3.2 × 106 C
3. 1.8 × 105 C
4. 4.1 × 104 C

Subtopic:  Faraday’s Law of Electrolysis |
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The number of Faradays required to produce 20.0 g of Ca from molten CaCl2 is-

1. 2F

2. 1F

3. 4F

4. 3F

Subtopic:  Faraday’s Law of Electrolysis |
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Three electrolytic cells A, B, C containing solutions of ZnSO4, AgNO3, and CuSO4, respectively are connected in series. A steady current of 1.5 amperes was passed through them until 1.45 g of silver was deposited at the cathode of cell B. The current flow time is-

1. 14 minutes

2. 25 minutes

3. 20 minutes

4. 11 minutes

Subtopic:  Faraday’s Law of Electrolysis |
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The correct increasing order of reducing the power of the metals is:

K+/K = –2.93 V
Ag+/Ag = 0.80 V
Hg2+/Hg = 0.79 V
Mg2+/Mg = –2.37 V
Cr3+/Cr = – 0.74 V

1. Cr < Mg < K < Ag < Hg

2. Mg < K < Ag < Hg < Cr

3. K < Ag < Hg < Cr < Mg

4. Ag < Hg < Cr < Mg < K

Subtopic:  Electrode & Electrode Potential |
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The correct statement about the given galvanic cell equation is -

Zn(s) + 2Ag+­­­(aq) → Zn2+(aq) + 2Ag(s)

1. The current will flow from silver to zinc in the external circuit.
2. The current will flow from zinc to silver in the external circuit.
3. The current will flow from silver to zinc in the internal circuit.
4. The current will flow from zinc to silver in the internal circuit.

Subtopic:  Electrolytic & Electrochemical Cell |
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 2Cr(s) + 3Cd2+(aq)  2Cr3+(aq) + 3Cd

ECr3+/Cr= -0.74 VECd2+/Cd=-0.40 V

The value of Gro in the above reaction will be - 

1. -196.83 kJ

2. 196.83 kJ

3. 186.83 kJ

4. -186.83 kJ

Subtopic:  Relation between Emf, G, Kc & pH |
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The incorrect statement(s) among the below is/are:

a. The unit of conductivity is S cm-2
b. Specific Conductivity of weak and strong electrolytes always decreases with a decrease in concentration.
c. The unit of molar conductivity is S cm-2 mol-1
d. Molar conductivity increases with an increase in concentration.

1. a

2. a and d

3. b and d

4. a and c

Subtopic:  Conductance & Conductivity |
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The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. The molar conductivity will be -

1. 124 S cm2 mol-1

2. 134 S cm2 mol-1

3. 128 S cm2 mol-1

4. 136 S cm2 mol-1

Subtopic:  Conductance & Conductivity |
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