The products obtained on the completion of the following reactions (i) and (ii) respectively are :

i.	C3H8(g) + 3H2O(g) \(\xrightarrow[Catalyst]{\Delta}\) A
ii.	\(\mathrm{Zn}_{(s)}+\mathrm{NaOH}_{(\mathrm{aq})} \xrightarrow[]{Heat}\)B

1. A = CO, and H₂ ; B = Na₂ZnO₂
2. A  = CO₂ ; B = Na₄ZnO₄
3. A = CH₃CH₂CH₂OH ; B=  ZnO
4. None of the above

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The consequences of high enthalpy of H–H bond in dihydrogen is /are :

The correct statement about electron-deficient hydride is that it:

The hydrides of carbon (C_nH_{2n + 2}) can act as -

1. Lewis acid.

2. Lewis base.

3. Both 1 and 2

4. None of the above

“Non-stoichiometric hydrides” are :

Metallic hydrides are useful for hydrogen storage because : 

1. Metallic hydrides are oxygen-rich.

2. Metallic hydrides are oxygen-deficient.

3. Metallic hydrides are hydrogen-rich.

4. Metallic hydrides are hydrogen-deficient.

Atomic hydrogen or oxy-hydrogen torch is used for cutting and welding purposes because:

 The correct order of hydrogen bonding among ${\mathrm{NH}}_3$, H2O and HF, is 

1. HF > ${\mathrm{H}}_2\mathrm{O}$ > ${\mathrm{NH}}_3$

2. ${\mathrm{H}}_2\mathrm{O}$ > HF > ${\mathrm{NH}}_3$

3. HF > ${\mathrm{NH}}_3$ > ${\mathrm{H}}_2\mathrm{O}$

4. ${\mathrm{NH}}_3$ > HF > ${\mathrm{H}}_2\mathrm{O}$

CO2  is used as a fire extinguisher because -

1. ${\mathrm{CO}}_2$ has high lattice energy.

2. ${\mathrm{CO}}_2$ will be effective in isolating the burning surface from dihydrogen and dioxygen.

3. ${\mathrm{CO}}_2$ is lighter than dioxygen.

4. ${\mathrm{CO}}_2$ is lighter than dihydrogen.

The term ’auto-protolysis’ of water means :